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AfilCa [17]
1 year ago
8

Which of the following examples is an error of addition by one? A. 7363 + 1535 = 8798 B. 3415 + 2174 = 5589 C. 5167 + 4622 = 978

9 D. 2683 + 6215 = 8898
Mathematics
2 answers:
Sloan [31]1 year ago
8 0

Answer:

(A) and (B)

Step-by-step explanation:

(A) The given example is:

7363 + 1535

Adding these two numbers, we get

8898

which is an error of addition by one.

Thus, this option is correct.

(B)The given example is:

3415 + 2174

Adding these two numbers, we get

6589

which is an error of addition by one.

Thus, this option is correct.

(C)The given example is:

5167+4622

Adding these two numbers, we get

9789

which is not an error of addition by one.

Thus, this option is not correct.

(D) The given example is:

2683+6215

Adding these two numbers, we get

8898

which is not an error of addition by one.

Thus, this option is not correct.

Amiraneli [1.4K]1 year ago
3 0

Answer:

A. 7363 + 1535 = 8798

Step-by-step explanation:

For A, when you add 7363 + 1535, you should get $8898 instead of 8798.

For the person that wrote B as an answer is wrong. B's addition is correct.

Hope this helps :D

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Answer:

\large\boxed{43^o}

Step-by-step explanation:

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In right triangle ABC, mC - 90° and AC BC. Which trigonometric ratio is cquivalent to sin b?
vaieri [72.5K]

Answer:

All trigonometric Ratios are  SinB = \frac{AC}{AB} ,  SinA= \frac{CB}{AB} ,  CosA= \frac{AC}{AB}

And  Cos B = \frac{CB}{AB}.

Step-by-step explanation:

Given that,

A right angle triangle ΔABC, ∠C =90°.

Diagram of the given scenario shown below,

In triangle ΔABC :-

                               Hypotenuse = AB\\Base = CB\\Perpendicular = AC

So,                            Sin\theta = \frac{perpendicular}{hypotenuse}

                                SinB = \frac{AC}{AB}

Now, for ∠A the dimensions of trigonometric ratios will be changed.

Here the base for ∠A is AC , perpendicular side is CB and hypotenuse will be same for all ratios.

                               SinA= \frac{CB}{AB}

Again,                    Cos\theta= \frac{base}{hypotenuse}

Then,                    CosA= \frac{AC}{AB}

And                      Cos B = \frac{CB}{AB}.

Hence,

All trigonometric Ratios are  SinB = \frac{AC}{AB} ,  SinA= \frac{CB}{AB} ,  CosA= \frac{AC}{AB}

And                      Cos B = \frac{CB}{AB}.

                               

8 0
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