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mario62 [17]
2 years ago
6

The center of a hyperbola is located at (0, 0). One focus is located at (0, 5) and its associated directrix is represented by th

e line y = 9/5 . Given the standard form of the equation of a hyperbola, what are the values of a and B
y^2/a^2 + x^2/b^2 = 1
A=
B=
Mathematics
2 answers:
Lady bird [3.3K]2 years ago
8 0
For a hyperbola   \dfrac{y^{2}}{a^{2}}-\dfrac{x^{2}}{b^{2}}=1
where   a^{2}+b^{2}=c^{2}
the directrix is the line   y=\dfrac{a^{2}}{c}
and the focus is at (0, c).

Here, we have c = 5, a² = 9, so b² = 5² - 9 = 16.
  a = √9 = 3
  b = √16 = 4

Your hyperbola's constants are ...
  a = 3
  b = 4


______
Please note that the equation of a hyperbola has a negative sign for one of the terms. The equation given in your problem statement is that of an ellipse.
tresset_1 [31]2 years ago
4 0

Answer:

a=3, b=4

Step-by-step explanation:

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FromTheMoon [43]

Answer:

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Step-by-step explanation:

(a) The Law of Sines can be used to find BD.

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  BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm

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(b) We can use the Law of Cosines to find AD.

  AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°

  AD^2 ≈ 110.841

  AD ≈ √110.841 ≈ 10.5281 . . . cm

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  A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°

  A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2

_____

Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.

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2 years ago
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Elanso [62]
To answer the question presented above, the conversion factor for km to feet is 1 kilometers is equal to 3280.84 feet. From the given,
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