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mario62 [17]
1 year ago
6

The center of a hyperbola is located at (0, 0). One focus is located at (0, 5) and its associated directrix is represented by th

e line y = 9/5 . Given the standard form of the equation of a hyperbola, what are the values of a and B
y^2/a^2 + x^2/b^2 = 1
A=
B=
Mathematics
2 answers:
Lady bird [3.3K]1 year ago
8 0
For a hyperbola   \dfrac{y^{2}}{a^{2}}-\dfrac{x^{2}}{b^{2}}=1
where   a^{2}+b^{2}=c^{2}
the directrix is the line   y=\dfrac{a^{2}}{c}
and the focus is at (0, c).

Here, we have c = 5, a² = 9, so b² = 5² - 9 = 16.
  a = √9 = 3
  b = √16 = 4

Your hyperbola's constants are ...
  a = 3
  b = 4


______
Please note that the equation of a hyperbola has a negative sign for one of the terms. The equation given in your problem statement is that of an ellipse.
tresset_1 [31]1 year ago
4 0

Answer:

a=3, b=4

Step-by-step explanation:

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