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Sophie [7]
2 years ago
6

A store ships cans by weight. A small box can hold 3 to 5 pounds. A medium box can hold 5 to 8 pounds. A large box can hold 8 to

10 pounds. The weights of the cans are given below. Drag cans into each box to show what the box could contain. (Imagine Math Answer)
Mathematics
1 answer:
Strike441 [17]2 years ago
6 0

Answer:

Step-by-step explanation: Uhh I have no idea how I got this right because I guessed but

small: 3-5 pounds 0.25+1.2+2.7

Medium: 5-8 pounds 0.25+0.25+1.2+1.2+1.2+1.2

Large 8-10 pounds 0.25+1.2+1.2+1.2+2.7+2.7

Hope I helped this is my first time answering a question have a good day everyone

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Three small circles C1, C2, and C3, each with radius 0.1 and centered at the origin are in the xy-, yz-, and xz-planes, respecti
den301095 [7]

Curl is defined as:

\bigtriangledown \times F=\frac{ \int F.dr}{Area}

Which can be rewritten as:

\frac{ \int F.dr}{Area}=\frac{ \int_{C_1} Fdr}{Area}\widehat{k}+\frac{ \int_{C_2} Fdr}{Area}\widehat{i}+\frac{ \int_{C_3} Fdr}{Area}\widehat{j}

This is because C1 lies on the xy plane and thus it's unit vector will be \widehat{k}.

By similar arguments the rest will follow too.

Now, area of each circle will be: \pi \times (0.1)^2=0.01 \pi

Therefore, Curl, as per our definition will be:

\frac{\int F.dr}{Area}=\frac{0.01\pi}{0.01\pi}\widehat{k}+\frac{0.4\pi}{0.01\pi}\widehat{i}+\frac{5 \pi}{0.01\pi}\widehat{j}

Thus, Curl=40\pi \widehat{i}+500\pi \widehat{j} +\widehat{k}

Which is the required answer.

7 0
2 years ago
ABCDEFGHIJ is a regular decagon. It rotates clockwise about its center to form the polygon A′B′C′D′E′F′G′H′I′J′. Match each angl
Lostsunrise [7]
A decagon has 10 sides.

It it is regular you can build 10 isosceles triangles from the center of the decagon to the 10 sides.

Each triangle has a common vertex where the angle of each triangle is 360° / 10 = 36°.

So each time that you rotate the decagon a multiple of 36° around the center you get an image that coincides with the original decagon.

If the letters are given clockwise:

- when you rotate 36° counter clockwise, the point A' (the image of A) will coincide with the point J.

- when you rotate 72° (2 times 36°) counter clockwise, the point A' will land on I.

- when you rotate 108° (3 times 36°) counter clockwise, the point A' will land on H.

- when you rotate 144° (4 times 36°) counter clockwise, the point A' will land on G.

- when you rotate 180° (5 times 36°) counter clockwise, the point A' will land on I.

- when you rotate 216° (6 times 36°) counter clockwise, the point A' will land on E.

- whn you rotate 252° (7 times 36°) counterclockwise, the point A' will coincide with D.

Add other 36° each time and A' will coincide successively with C, B and the same A.
8 0
2 years ago
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Gabriel makes a model of a pyramid with the dimensions shown. A square pyramid. The square base has side lengths of 12 inches. T
Blizzard [7]

Answer:

The area of the square base is 114 in. 2

The area of each triangular face is 66 in. 2

Gabriel will need 408 in. 2  of paint

8 0
2 years ago
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SAT Writing scores are normally distributed with a mean of 491 and a standard deviation of 113.A university plans to send letter
Sholpan [36]

Answer:

z=1.405

And if we solve for a we got

a=491 +1.405*113=649.765

So the value of height that separates the bottom 92% of data from the top 8% is 649.765.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(491,113)  

Where \mu=491 and \sigma=113

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.08   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.92 of the area on the left and 0.08 of the area on the right it's z=1.405. On this case P(Z<1.405)=0.92 and P(z>0.92)=0.08

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.405

And if we solve for a we got

a=491 +1.405*113=649.765

So the value of height that separates the bottom 92% of data from the top 8% is 649.765.  

6 0
2 years ago
A mirror is made of two congruent parallelograms as shown in the diagram. The parallelograms have a combined area of 9 1/3 squar
Vika [28.1K]
Given:
2 parallelograms with an area of 9 1/3 yd²
height of each parallelogram is 1 1/3 yd

Area of parallelogram = base * height

We need to divide the combined area into two to get each parallelogram's base.

9 1/3 = ((9*3)+1)/3 = 28/3

28/3 ÷ 2 = 28/3 * 1/2 = 28/6 yd² or 4 4/6 yd² ⇒ 4 2/3 yd²

Area of each parallelogram is 4 2/3 yd²

4 2/3 yd² = base * 1 1/3 yd

14/3 yd² ÷ 4/3 yd = base

14/3 yd² x 3/4 yd = base
14*3 / 3*4 = base
42 / 12 = base
3 6/12 yd = base
or 3 1/2 yd = base

a) the base of each parallelogram is 3 1/2 yards
b) we can assume that the two parallelograms form a rectangle.
area of a rectangle is length times width.

length is 3 1/2 yds * 2 = 7 yds
width is 3 1/2 yds

Area of rectangle = 7 yds * 3 1/2 yds
Area = 7 yd * 7/2 yd
Area = 7*7 / 2 yd²
Area = 49 / 2 yd²
Area = 24 1/2 yd²


8 0
1 year ago
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