So for number there are 6 possible outcomes nad 5 is one of them so 1/6
He next one there are 2 outcomes and heads is 1 outcome so 1/2
For the next one you have to multiply them together so you get 1/12
And the events are independent because whatever you roll on the die won’t affect the coin(it actually does on a very small scale but I don’t think you go into that much detail for high school maths)
The data has been properly arranged in tabular form and is shown below in the image.
First we need to find the mean and median of scores of both students.
1) For Amo:
Mean =

Median = Middle Value when data is arranged in ascending order = 90
2) For Javier:
Mean =

Median = Middle Value when data is arranged in ascending order = 92
For both the students, value of Median is larger then the mean. So in order to give the best possible grade Mr. Malloy should use the median score for both students.
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➷ a/sinA = c/sinC
Substitute in the values:
37/sin(42) = c/sin(41.5)
Multiply both sides by sin(41.5)
37/sin(42) x sin(41.5) = c
Solve:
c = 36.63999457
The correct answer would be C. 36.64
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Answer:
Mean is 3.05
Standard deviation is 1.69.
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they are foreign, or they are not. This means that we can solve this problem using concepts of the binomial probability distribution.
Binomial probability distribution
The probability of x sucesses on n repeated trials, with p probability.
In this problem, we have a sample of 50 students, so
. The proportion of all UNC students that are foreign students is 0.061, so
.
The mean is given by the following formula:

The standard deviation is given by the following formula:

Hello there,
There is a total of 40 animals in that in 10 zebras, 10 lions, 10 elephants, and 10 monkeys.
So the probability of them both being lions is pretty rare. 2/40 so that would give you a 1/20 chance of both crackers being both lions.
I hope this helps!