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son4ous [18]
2 years ago
9

Gabriel makes a model of a pyramid with the dimensions shown. A square pyramid. The square base has side lengths of 12 inches. T

he triangular sides have a height of 11 inches. Gabriel wants to paint the model. How much paint will he need? The area of the square base is in.2. The area of each triangular face is in.2. Gabriel will need in.2 of paint.

Mathematics
2 answers:
Blizzard [7]2 years ago
8 0

Answer:

The area of the square base is 114 in. 2

The area of each triangular face is 66 in. 2

Gabriel will need 408 in. 2  of paint

murzikaleks [220]2 years ago
8 0
<h2><u><em>Answer</em></u></h2><h2><u><em /></u>144in^{2}<u><em /></u></h2><h2><u><em /></u>66in^{2}<u><em /></u></h2><h2><u><em /></u>408in^{2}<u><em /></u></h2><h2></h2>

<u><em /></u>

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Answer:

a) For this case we can use the binomial model since we assume independent events and the same probability for each trial is the same p =0.15

b) P(X=0)=(10C0)(0.15)^0 (1-0.15)^{10-0}=0.1969

c) P(X=3)=(10C3)(0.15)^3 (1-0.15)^{10-3}=0.1298

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And using the result from part a we got:

P(X \geq 1)= 1-P(X

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n p)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Part a

For this case we can use the binomial model since we assume independent events and the same probability for each trial is the same p =0.15

Part b

For this case we want this probability:

P(X=0)

And replacing we got:

P(X=0)=(10C0)(0.15)^0 (1-0.15)^{10-0}=0.1969

Part c

For this case we want this probability:

P(X=3)

And replacing we got:

P(X=3)=(10C3)(0.15)^3 (1-0.15)^{10-3}=0.1298

Part d

For this cae we want thi probability:

P(X \geq 1)

And we can use the complment rule and we got:

P(X \geq 1)= 1-P(X

And using the result from part a we got:

P(X \geq 1)= 1-P(X

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Answer:

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