Tan 2° = x / 1 mile, where x is the vertical change
0.03492 = x / 1 mile
x = 1 mile · 0.03429 = 0.03492 miles
1 mile = 5,280 feet
0.03492 · 5,280 = 184.38 ft
Answer: The vertical change is 184.38 feet
Salt flows in at a rate of (5 g/L)*(3 L/min) = 15 g/min.
Salt flows out at a rate of (x/10 g/L)*(3 L/min) = 3x/10 g/min.
So the net flow rate of salt, given by 
in grams, is governed by the differential equation,
which is linear. Move the 
term to the right side, then multiply both sides by 
:
Integrate both sides, then solve for :
Since the tank starts with 5 g of salt at time 
, we have
The time it takes for the tank to hold 20 g of salt is 
such that
PART I
Angular size of the minor arc .
Half of the chord an the radius makes a right angled triangle with the radius as the hypotenuse and half of the chord as one of the shorter side.
Therefore, using trigonometric ratio, sine = opp/hyp
sine θ = 8/10 where θ is half the minor angle
θ = 53.13
Therefore, the angular size of the minor arc will be 53.13 × 2 = 106.26°
PART II
The length of an arc is given by (θ/360 )× 2πr
where θ is the angle subtended by the arc to the center of the circle and r is the radius of the circle.
Therefore, length = (106.26/360) × 3.142 × 2×10
= 18.548 Inches
Answer:
5 tablets can be bought
Step-by-step explanation:
47/8= 5
