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777dan777 [17]
2 years ago
6

A bank is offering home loans at an interest rate of 5 1/2%. Write the percent as a fraction in simplest form.

Mathematics
2 answers:
beks73 [17]2 years ago
8 0
5 1/2%=5.5%
5.5%=5.5/100=55/1000
55/1000=11/200
AlekseyPX2 years ago
5 0

Answer:

The percent as a fraction in simplest form is 5\frac{1}{2}\%=\frac{11}{200}  

Step-by-step explanation:

Given : A bank is offering home loans at an interest rate of 5\frac{1}{2}\%.

To find : Write the percent as a fraction in simplest form ?

Solution :

Interest rate is  5\frac{1}{2}\%

Convert mixed fraction into improper fraction,

5\frac{1}{2}\%=\frac{11}{2}\%

Converting percentage by dividing number by 100,

5\frac{1}{2}\%=\frac{11}{2}

5\frac{1}{2}\%=\frac{11}{2}\times \frac{1}{100}

5\frac{1}{2}\%=\frac{11}{200}

Therefore, The percent as a fraction in simplest form is 5\frac{1}{2}\%=\frac{11}{200}

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Alright, so he has an <em>annual </em>salary of 47,000 dollars. Which means that he is paid 47,000 dollars in 12 months. You'll first have to calculate the pay Vijay receives <em>each month</em>, which is \frac{47,000}{12 months}, or about $3,916.67 (I'll round up to 3917 for simplicity). 

Now, he gets paid twice a month. So each paycheck is half of $3917. 3917 x (1/2) = $1958.50. 

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6 0
1 year ago
Mark and Sofia walk together down a long, straight road. They walk without stopping for 4 miles. At this point Sofia says their
Marina CMI [18]

Answer:

Sofia is correct.

Step-by-step explanation:

Mark's statement depends on the starting point. He can be correct if they started at the 0 mile, but in this case we don't know where they started. They could had started at the 12 mile and their current position after the walking would be 16 miles.

On the other hand, Sofia's statement doesn't depend on where they started. She refers to how much they walked, not to where they are after the walking. Since they stopped after 4 non-stopping miles, their displacement was exactly 4 miles. So Sofia is correct.

5 0
1 year ago
At the movies, a couple bought 2 medium drinks and a large popcorn for $13.85. At the same theater, a family bought 3 medium dri
m_a_m_a [10]

Answer:

a) the cost of one medium drink be $3.80

b) the cost of a large popcorn be $6.25

Step-by-step explanation:

Let the cost of one medium drink be $x

and the cost of a large popcorn be $y

According to question,

A couple bought 2 medium drinks and a large popcorn for $13.85.

2x + y = 13.85      ..............(1)

A family bought 3 medium drinks and 2 large popcorn for a total of $23.90

3x + 2y = 23.90      ..............(2)

Using Elimination method to solve the system of equation,

Multiply equation (1) by 2 , we get,

4x + 2y = 27.70      ..............(3)

Now, subtract equation (2) from (3), we get,

4x + 2y-(3x + 2y) = 27.70 - 23.90

4x + 2y-3x - 2y = 3.80

4x -3x = 3.80

x = 3.80

Substitute, x = 3.8 in (1) ,

2(3.80) + y = 13.85  

7.60 +y = 13.85

y = 6.25

Therefore, the cost of one medium drink be $3.80

and the cost of a large popcorn be $6.25



7 0
1 year ago
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Which shows the four-term polynomial and factored form of x2 + 6x-27?
blsea [12.9K]

Answer:

0x2+9x-3x-27      6x-27

Step-by-step explanation:

7 0
1 year ago
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On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number
Alina [70]
<h3><u><em>Question:</em></u></h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3><em><u>Answer:</u></em></h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3><em><u>Solution:</u></em></h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

<u><em>Given items were sold for $356</em></u>

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

c \times 8 + p \times 10 = 356

8c + 10p = 356  ----- eqn 2

<u><em>Let us solve eqn 1 and eqn 2</em></u>

From eqn 1,

p = 40 - c    ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

<em>Substitute c = 22 in eqn 3</em>

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0
2 years ago
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