The figure below shows the ideal pattern of movement of a herd of cattle, with the arrows showing the movement of the handler as
2 answers:
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Answer:
37.23% probability that randomly selected homework will require between 8 and 12 minutes to grade
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that randomly selected homework will require between 8 and 12 minutes to grade?
This is the pvalue of Z when X = 12 subtracted by the pvalue of Z when X = 8. So
X = 12
has a pvalue of 0.4052
X = 8
has a pvalue of 0.0329
0.4052 - 0.0329 = 0.3723
37.23% probability that randomly selected homework will require between 8 and 12 minutes to grade
Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the AC = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
Answer:
Therefore the only statement that is not true is b.)
Step-by-step explanation:
There employees are 6 secretaries, 5 consultants and 4 partners in the firm.
a.) The probability that a secretary wins in the first draw
=
b.) The probability that a secretary wins a ticket on second draw. It has been given that a ticket was won on the first draw by a consultant.
p(secretary wins on second draw | consultant wins on first draw)
=
= .
The probability that a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw = is not true.
The probability that a secretary wins on the second draw =
c.) The probability that a consultant wins on the first draw =
d.) The probability of two secretaries winning both tickets
= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)
=
Therefore the only statement that is not true is b.)