Answer:
a) mt = -2
b) y=2-2x
Step-by-step explanation:
We have 
⇒ 
and we must find
a) The slope of the tangent line to the curve at the point (1,0)
b) The equation of the tangent line in part (a)
a) with the point (1,0) then f'(x) 
the slope (mt) in x=1 is
f'(1)=
, m t= -2
b) mt=-2 at the point (1,0), knowing that the pending point model is:
, we solve y-0 = -2(x-1) ⇒ y=-2x+2
Answer:
The answer is 135 degrees.
Step-by-step explanation:
As we are given the position. If we take the <u>derivative</u>, we get the velocity vector. If we take the <u>derivative</u> again, we find the acceleration vector of the particle.
At time t=0;
As i attach in the picture the angle between the velocity and acceleration vector is 
degrees
Answer:
Use the regression calculator to compare the teams’ number of runs with their number of wins.
A 2-column table with 9 rows. Column 1 is labeled R with entries 808, 768, 655, 684, 637, 619, 613, 609, 563. Column 2 is labeled W with entries 93, 94, 66, 81, 86, 75, 61, 69, 55.
What is the y-intercept of the trend line, to the nearest hundredth?
Step-by-step explanation:
0.5625 is the answer I got. Hope this helps. Leave a thanks if so. ☺♥
