Answer:
This is possible.
Step-by-step explanation:
We can say that m<E=m<E, because of the Reflexive Property
Then, we have angles JKL and ELJ, which are equal through the peripheral angle theorem.
With these two angles, we can say that triangles ELK and EJL are similar, by the Angle-Angle Postulate (AA).
Then we can create this ratio through the Corresponding Parts of Similar Triangles Theorem, (CPST), 
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With this ratio, we can cross multiply to get the desired result
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Hope this helps with your RSM problem
Yup, i caught ya.
The answer is 0.81 since you have to (x) 0.60x 1.35=0.81
Than you divide 0.81÷0.60
So 72 pencils and 24 calculators
so greates number of identical calculators
this means
what is the biggest number that we can divide 72 and 24 by and get a whole number
this is called the GCM or greatest common multipule
to find the GCM, you factor 72 and group the like ones
72=2 times 2 times 2 times 3 times 3
24=2 times 2 times 2 times 3
so the common group is 2 times 2 times 2 times 3 or 24
so the greates number of packs is 24
so pencils
72 divided by 24=72/24=3
3 pencils per pack
24 divided by 24=24/24=1
1 calulator per pack
answer is 3 pencils and 1 calculator per pack
Answer:
(a) (-12/13, 5/13)
(b) (12/13, -5/13)
(c) (-12/13, -5/13)
(d) (12/13, 5/13)
Step-by-step explanation:
(a) The terminal point is effectively reflected across the y-axis, so the sign of the x-coordinate changes. (-12/13, 5/13)
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(b) The terminal point is effectively reflected across the x-axis, so the sign of the y-coordinate changes. (12/13, -5/13)
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(c) The terminal point is effectively reflected across the origin, so the signs of both coordinates change. (-12/13, -5/13)
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(d) The terminal point is mapped to itself, so its coordinates remain unchanged. (12/13, 5/13)
