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VLD [36.1K]
2 years ago
9

Zayed is helping his classmates get ready for their math test by making them identical packages of pencils and calculators. He h

as 72 pencils and 24 calculators and he must use all of the pencils and calculators. If Zayed creates the greatest number of identical packages possible, how many ls will be in each package?
Mathematics
2 answers:
oee [108]2 years ago
6 0
So 72 pencils and 24 calculators
so greates number of identical calculators

this means
what is the biggest number that we can divide 72 and 24 by and get a whole number
this is called the GCM or greatest common multipule

to find the GCM, you factor 72 and group the like ones
72=2 times 2 times 2 times 3 times 3
24=2 times 2 times 2 times 3
so the common group is 2 times 2 times 2 times 3 or 24
so the greates number of packs is 24

so pencils
72 divided by 24=72/24=3
3 pencils per pack

24 divided by 24=24/24=1
1 calulator per pack


answer is 3 pencils and 1 calculator per pack
Lena [83]2 years ago
3 0

3  pencils per box.

The GFC of 72 and 24 is 24. 72 divide by 24 is 3, 24 divided by 24 is 1.

Therefore, there are 3 pencils and 1 calculator each box. To answer your question, 3  pencils per box.

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Answer:The answer is 98

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The area on a wall covered by a rectangular poster is 294 square inches. The length of the poster is 1.5 times longer than the w
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Hey there,

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2 years ago
Read 2 more answers
Emily invests $5,000 in an
Gemiola [76]

Answer:

50 years

Step-by-step explanation:

use the simple interest formula :

PRT/100

P is the principle (5000)

R is the rate of interest (4)

T is the time taken (x- unknown)

the amount at the end is double the amount invested  = 5000*2 = 10000

(5000*4 * x )/100 = 10000

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20000x = 100*10000

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Bones Brothers &amp; Associates prepare individual tax returns. Over prior years, Bones Brothers have maintained careful records
madreJ [45]

Answer:

For this case we have the following info related to the time to prepare a return

\mu =90 , \sigma =14

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation would be:

\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2

And the best answer would be

b. 2 minutes

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we have the following info related to the time to prepare a return

\mu =90 , \sigma =14

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation would be:

\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2

And the best answer would be

b. 2 minutes

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2 years ago
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