Answer: cos(53o)=y/5
<span>T
riangle abc is a right triangle and sin(53o) = . solve for x and round to the nearest whole number. which equation correctly uses the value of x to represent the cosine of angle a?cos(53o) = 4/xcos(53o) = y/5cos(53o) = x/4cos(53o) = 5/y</span>
Step-by-step explanation:
a) 7!
If there are no restrictions, answer is 7! as it is the permutation of all animals.
b) 4! x 3!
As cats are 6 and Dogs are 5, thus 1st and last must be cats in order to have alternate arrangements. Therefore the only choices are the order of the cats among themselves and the order of the dogs among themselves. There
are 4! permutations of the cats and 3! permutations of the dogs,
so there are a total of 4! x 3! possible arrangements of the suites.
c) 3! x 5!
There are 3! possible arrangements of the dogs among themselves. Now, if we consider the dogs as one ”object” together, then we can think of arranging the 4 cats together with this 1 additional object. There are 5! such arrangements possible, so there are a total of 3! · 5! possible arrangements of the suites.
d) 2 x 4! x 3!
As required that all the cats must be together and all the dogs must be together, either the cats are all before the dogs or the dogs are all before the cats. There are two possible arrangements thus two times of both possibilities is the answer i.e. 2 x 4! x 3!
We know that
volume of <span>a rectangular prism =B*h------> equation 1
where
B is the area of the base
h is the height
volume of </span><span>a rectangular pyramid=(1/3)*B*h-----> equation 2
where
</span>B is the area of the base
h is the height
<span>
substitute equation 1 in equation 2
</span>volume of a rectangular pyramid=(1/3)*volume of a rectangular prism
<span>
the answer part a) is
</span>volume of a rectangular pyramid=(1/3)*volume of a rectangular prism
<span>
Part b) </span><span>If the pyramid was full of water, how much of the prism would it fill up?
</span>
the answer part b) is
<span>If the pyramid was filled with water, the prism would only fill 1/3 of its volume
Part c) </span><span>Name another pair of three-dimensional objects that have a relationship similar to this
cones and cylinders
</span>volume of a cylinder =B*h------> equation 1
where
B is the area of the base
h is the height <span>
</span>volume of a cone=(1/3)*B*h-----> equation 2
where
B is the area of the base
h is the height
substitute equation 1 in equation 2
volume of a cone=(1/3)*volume of a cylinder
Answer: f(2) = 4
Step-by-step explanation:
F(x) and g(x) are said to be continuous functions
Lim x=2 [3f(x) + f(x)g(x)] = 36
g(x) = 2
Limit x=2
[3f(2) + f(2)g(2)] = 36
[3f(2) + f(2) . 6] = 36
[3f(2) + 6f(2)] = 36
9f(2) = 36
Divide both sides by 9
f(2) = 36/9
f(2) = 4
