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allochka39001 [22]
2 years ago
11

Juanita and Samuel are planning a pizza party. They order a rectangle sheet pizza that measures 21 inches by 36 inches.?They tel

l the pizza maker not to cut it because they want to cut it themselves. All pieces of pizza must be square with none left over. What is the side length of the largest square pieces into which Juanita and Samuel can cut the pizza? How many pieces of this size can be cut?
Mathematics
1 answer:
saveliy_v [14]2 years ago
7 0
First, find the total area of pizza. The area of a rectangle is length times width. 

Area = 21 x 36 = 756 sq. inches

Now, we must divide the total area with the largest square possible without any excess. So, we equate the area of the pizza to area of square:

A = s² = 756
s = 6 √21

Hence, the largest piece square possible has a side of 6 inches. Then, we divide the total area of the pizza by the area of each square piece to find the number of pieces;

756/6² = 21

Thus, there would be 21 pieces of 6-in square piece of pizza.
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On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, 1) and (0, 3). Everything to th
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Answer:

y>\frac{2}{3}x+3

Step-by-step explanation:

step 1

Determine the slope of the dashed line

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

(-3,1) and (0,3)

substitute

m=\frac{3-1}{0+3}

m=\frac{2}{3}

step 2

Find the equation of the dashed line in slope intercept form

y=mx+b

we have

m=\frac{2}{3}

b=3 ---> given problem

substitute

y=\frac{2}{3}x+3

step 3

Find the equation of the inequality

we know that

Is a dashed line and everything to the left of the line is shaded

so

y>\frac{2}{3}x+3

see the attached figure to better understand the problem

8 0
2 years ago
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A coin has a radius of 10 mm. How long will it take the coin to roll through the given angle measure at the given angular veloci
Gemiola [76]

Answer:

t = 1.57 sec

distance, d = 98.65 mm

Step-by-step explanation:

Given an angle of 540°

At 6 revolutions per second, which is the angular velocity.

Radius, r = 10 mm

We are asked to find the time and the distance.

To find the time, let's use the formula:

\theta = a*t

Where \theta = angle in radians.

Converting 540° to radians, we have:

\theta = 540 * \frac{\pi}{180} = 9.42 rad

Therefore, from the formula, let's find t.

\theta = a*t

9.42 = 6 * t

t = \frac{9.42}{6} = 1.57

time = 1.57

To find the distance, we have:

\frac{1.57 * 360}{360} = \frac{d}{2 \pi r}

\frac{1.57 * 360}{360} = \frac{d}{2\pi 10}

1.57 = \frac{d}{20\pi}

d = 20 \pi *1.57

d = 98.65 mm

Therefore, the time is 1.57 seconds and the distance is 98.65 mm

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Raj wants to take yoga classes. There are two yoga studios that have different membership plans.
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A new car is purchased for 20300 dollars. The value of the car depreciates at 9.5% per year. What will the value of the car be,
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The starting value is 20,300, and the value is decreasing by 9.5% each year.

Because it decreases by 9.5% each year based on the previous amount, we use an exponential decay model.

A decrease by 9.5% corresponds to multiplying by 91.5% each year.

We write . We plug in 11 years for t.

A(t)=23000(0.915)^{t}\\\\A(11)=23000(0.915)^{11}\\\\A(11)=7671.18

$7,671.18
6 0
2 years ago
Part A What is the electric field at the position (x1,y1)=(5.0 cm , 0 cm) in component form? Express your answer in terms of the
erik [133]

The complete Question is

A −12 nC charge is located at (x, y)=(1.0 cm, 0 cm).

Part A) What is the electric field at the position (x1, y1)=(5.0 cm, 0 cm) in component form?

Part B) What is the electric field at the position (x2, y2)=(−5.0 cm, 0 cm) in component form?

Part C) What is the electric field at the position (x3, y3)=(0 cm, 5.0 cm) in component form?

Express your answer in terms of the unit vectors i^ and j^. Use the 'unit vector' button to denote unit vectors in your answer.

Answer:

A)  E = - 67500i + 0j N/C

B)   E = 30000i + 0j N/C

C)  E = 8143.18i -  -40715.66j N/C

Step-by-step explanation:

Part A)

Magnitude of the charge = Q = -12 nC = -12 \times 10^{-9} C

Since, its the negative charge, the direction of Electric Field lines will be directed toward the charge

Location of the charge = (1, 0)

We need to find the electric field at point (5, 0)

The formula for the magnitude of electric field due to a point charge is:

E=\frac{kQ}{r^{2}}

Here,

k = Coulomb's Law Constant = 9 \times 10^{9}

Q = Magnitude of the charge

r = Distance between the charge and the point where we need to find the value of E

We can find r by using the Distance Formula.

So,

r=\sqrt{(5-1)^{2}+(0-0)^{2}}=4 cm = 0.04 m

Using these values in the formula, we get:

E=\frac{9\times 10^{9} \times 12 \times 10^{-9}}{(0.04)^{2}}= 67500 N/C

Since, two point (5, 0) is to the right of the given charge (as shown in the first image) i.e. in horizontal direction, all of the electric field experienced by it will be in horizontal direction and the vertical component would be zero. Also the direction of Electric field will be towards the charge i.e. in left direction so the x-component of Electric field will be negative.

Thus, we can write the value of E in vector form to be:

E = - 67500i + 0j N/C

Part B)

We need to find the Electric Field at point (-5, 0)

Using the similar procedure as used in the previous step, first we find r:

r=\sqrt{(-5-1)^{2}+(0-0)^{2}}=6 cm = 0.06

Using the values in the formula of Electric field, we get:

E = \frac{9 \times 10^{9} \times 12 \times 10^{-9}}{(0.06)^2}=30000 N/C

In this case again, the point is located in a horizontal direction to the given charge, so all the Electric Field experienced by it will be in horizontal direction and the vertical component will be zero. The direction of Electric field will be towards the charge i.e towards Right, so the x-component will be positive in this case.

So, value of the electric field in component form would be:

E = 30000i + 0j N/C

Part C)

We need to find the value of electric field at the point (0, 5). First we find the value of r:

r=\sqrt{(1-0)^2+(0-5)^2}=\sqrt{26}=5.1 cm = 0.051 m

Using the values in the formula of E, we get:

E=\frac{kQ}{r^{2}}=\frac{9 \times 10^{9} \times 12 \times 10^{-9}}{(0.051)^{2}}=41522 N/C

The point (0, 5) is neither exactly to the left or exactly up. So, for this point we need to find both the horizontal and vertical components as shown in the 2nd figure below.  

From the triangle, we have the opposite and adjacent side to the angle, so using the tangent we can find the value of angle theta.  

tan(\theta)=\frac{5}{1}\\\theta=tan^{-1}(5)=78.69

The two angles shown in the figure will be equal as there are alternate interior angles. Now the angle which E will make with positive x-axis will lie in the 4th quadrant as it lies below the horizontal line. So, the angle with positive x-axis would be:

360 - 78.69 = 281.31 degrees

Ex = E cos(θ) = 41522 cos(281.31) = 8143.18 N/C

Ey = E sin(θ) = 41522 sin(281.31) = -40715.66 N/C

So, in component form the Electric field will be:

E = 8143.18<em>i</em> -  -40715.66<em>j</em>

3 0
2 years ago
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