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Llana [10]
2 years ago
14

How many numbers are 10 units from zero on number line

Mathematics
2 answers:
Neko [114]2 years ago
6 0

Answer:

2

Step-by-step explanation:

The reason I said 2 is becasue you could go left and right. To the left of 0 is negitive numbers and to the right of 0 id positive numbers. So 10 units to the right of 0 is 10. Ten units to the left of zero is -10.

Hopefuly this helped you! Please tell me if I am Incorrect. That would be a great help.  

Lelu [443]2 years ago
4 0

Answer:

I think 2.

Step-by-step explanation:

10, and negative ten

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Find the value of x, &amp; y.<br> 3x-y+8x-7=x+2y+5x+3y
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Please rewrite this equation(s) using parantheses than needed 

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In a large population, 61 % of the people have been vaccinated. if 4 people are randomly selected, what is the probability that
muminat
In a large population, 61% of the people are vaccinated, meaning there are 39% who are not. The problem asks for the probability that out of the 4 randomly selected people, at least one of them has been vaccinated. Therefore, we need to add all the possibilities that there could be one, two, three or four randomly selected persons who were vaccinated.

For only one person, we use P(1), same reasoning should hold for other subscripts.

P(1) = (61/100)(39/100)(39/100)(39/100) = 0.03618459
P(2) = (61/100)(61/100)(39/100)(39/100) = 0.05659641
P(3) = (61/100)(61/100)(61/100)(39/100) = 0.08852259
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Adding these probabilities, we have 0.319761. Therefore the probability of at least one person has been vaccinated out of 4 persons randomly selected is 0.32 or 32%, rounded off to the nearest hundredths.
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1 year ago
From generation to generation, the mean age when smokers first start to smoke varies. However, the standard deviation of that ag
Jlenok [28]

Answer:

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the the actual mean starting age of smokers is significantly lower than 19.      

Step-by-step explanation:

1) Data given and notation      

\bar X=18.1 represent the mean age when smokers first start to smoke varies  

s=1.3 represent the standard deviation for the sample  

\sigma=2.1 represent the population standard deviation  

n=37 sample size      

\mu_o =5.7 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean starting age is at least 19, the system of hypothesis would be:      

Null hypothesis:\mu\geq 19      

Alternative hypothesis:\mu < 19      

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:      

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)      

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

z=\frac{18.1-19}{\frac{2.1}{\sqrt{37}}}=-2.607      

Calculate the P-value      

Since is a one-side lower test the p value would be:      

p_v =P(z  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the the actual mean starting age of smokers is significantly lower than 19.      

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Answer:

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