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DENIUS [597]
2 years ago
8

Which expression is equivalent to the following complex fraction? StartFraction 1 Over x EndFraction minus StartFraction 1 Over

y EndFraction divided by StartFraction 1 Over x EndFraction + StartFraction 1 Over y EndFraction
Mathematics
2 answers:
Darina [25.2K]2 years ago
6 0

Answer:

\frac{y-x}{x+y}

Step-by-step explanation:

We are given that fraction

\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}

We have to find the expression which is equivalent to given  fraction .

\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy}

\frac{1}{x}+\frac{1}{y}=\frac{x+y}{xy}

Substitute the values  then, we get

\frac{\frac{y-x}{xy}}{\frac{y+x}{xy}}

We know that

\frac{\frac{a}{b}}{\frac{x}{y}}=\frac{a}{b}\times \frac{y}{x}

Using the property then, we get

\frac{y-x}{xy}\times \frac{xy}{x+y}

\frac{y-x}{x+y}

This is required expression which is equivalent to given expression.

avanturin [10]2 years ago
6 0

Answer: It’s D

Step-by-step explanation:

Took quiz on edge

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there are two identical fridges for desserts. one of the fridge has 5/8 of its room left and the other fridge is only 1/8 full.
ELEN [110]

Answer:

1.5

Step-by-step explanation:

5/8 + 7/8= 1.5 or 1  1/2

6 0
2 years ago
Read 2 more answers
Tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 28% below the target pressure.
Alona [7]

Answer:

Step-by-step explanation:

Hello!

The monitoring system warn the driver when the tire pressure of the vehicle is 28% below target pressure.

Be X: target tire pressure of a certain car (pounds per square inch)

a)

X= 28 psi

If the monitoring system will warn the driver when the pressure is 28% below the target pressure: X-0.28X

First step, you have to calculate the 28% of 28psi

28*0.28= 7.84

Second step, is to subtract the calculated 28% to the target pressure:

28 - 7.84= 20.16

The TPMS will trigger a warning at 20.16 psi.

b)

If X~N(μ;σ²)

μ= 28psi (since the average is on target, then the target pressure for the car will be the average value of the distribution)

σ= 3psi

P(X≤20.16)

The standard normal distribution is tabulated. Any value of any random variable X with normal distribution can be "converted" by subtracting the variable from its mean and dividing it by its standard deviation.

So to calculate each of the asked probabilities, you have to first, "transform" the value of the variable to a value of the standard normal distribution Z, then you use the standard normal tables to reach the corresponding probability.

Z= (X-μ)/σ= (20.16-28)/3= -2.61

Now you have to look for the corresponding value of probability using the Z-table. Since the value is negative you have to the use the left entry of the Z-table, in the first column you'll find the integer and first decimal of the value -2.6- and in the first row you'll find the second decimal value -.-1

The value of probability that corresponds to -2.61 is:

P(Z≤-2.61)= 0.005

c)

You have to calculate the probability of inspecting a tire at random and it being inflated within recommended range, symbolically this is:

P(30≤X≤26)= P(X≤30)-P(X≤26)

Calculate both Z values:

Z= (30-28)/3= 0.67

Z= (26-28)/3= -0.67

P(Z≤0.67)-P(Z≤-0.67)= 0.749 - 0.251= 0.498

The probability of the tire being inflated within recommended inflation range is 0.498.

I hope this helps!

5 0
2 years ago
Which of the following is a point of tangency on the circle below?<br> Help ASAP please
kumpel [21]

Answer:

Point B

Step-by-step explanation:

a point of tangency on a circle is where an outside line touches the outer circle at one point (the outside line touching it only once is what makes that line a tangent) so in this case the point of tangency is Point B

Please mark as Brainliest :)

6 0
2 years ago
Please help fast
lions [1.4K]
C. A chord because a chord is a line segment with 2 end points
5 0
2 years ago
A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0
2 years ago
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