I think Mr. Han is around the 60 or 70 age.
I am really sorry that I couldn't answer this problem. Try starting with 21 and multiply that by 3. To check if you can do it, add 43 to the number you multiply 3 with. Again, i am really sorry that i only wrote a hint. Good luck finding the answer!
To solve the quadratic equation given by 0=x^2-9x-20, we use the quadratic formula given by:
x=[-b+\- sqrt(b^2-4ac)]/(2a)
where,
a=1,b=-9,c=-20
thus substituting the above values into our formula we get:
x=[9+\-sqrt(9^2-4(-20*1))/(2*1)
x=[9+\-sqrt(161)]/2
x=[9+sqrt161]/2 or x=[9-sqrt161]/2
Answer:
Step-by-step explanation:
hello :
100+(n-2)² = 149
100-100+(n-2)² = 149-100
(n-2)² = 49
(n-2)² - 49 =0 but 49=7²
(n-2)² - 7² =0 use identity : a²-b²=(a-b)(a+b)
(n-2-7)(n-2+7)=0
(n-9)(n+5)=0
n-9=0 or n+5=0
n=9 or n=-5
The outcome A="At least one" means {1,2,3,4,5......n} where n is the maximum possible outcome.
The only other outcome (B) left (i.e. the complement of the above event "at least one") is (B)={0}.
Therefore, by Kolmogorov's second axiom, A and B are complements, and
P(A)+P(B)=1
therefore
P(A)=1-P(B), or in words,
Probability of outcomes of "at least one" is the complement of the outcome of "0" item.
