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1 year ago

Which is equivalent toStartRoot 10 EndRoot Superscript three-fourths x ?

Mathematics

1 answer:

DENIUS [597]1 year ago

4 0

Answer:

I THINK its the last one (8 root 10 to the power of 3x)

Step-by-step explanation:

A square root is the same thing as raising something to the 1/2. So the expression we have is (10^1/2)^3/4x.

Due to exponent rules we can multiply to get

10^3/8x which is the same thing as 10^3x/8

The 8 goes to the root and the 3x becomes the exponent

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Ryan goes the mall with his friends after school. At the mall he purchases four pairs of basketball shorts and a pair of sneaker

Korvikt [17]

Answer:

$25.00

Step-by-step explanation:

200-100=100

100/4=25

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1 year ago

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Initially 5 grams of salt are dissolved into 10 liters of water. Brine with concentration of salt 5 grams per liter is added at

DiKsa [7]

Salt flows in at a rate of (5 g/L)*(3 L/min) = 15 g/min.

Salt flows out at a rate of (x/10 g/L)*(3 L/min) = 3x/10 g/min.

So the net flow rate of salt, given by $x(t)$ in grams, is governed by the differential equation,

$x'(t)=15-\dfrac{3x(t)}{10}$

which is linear. Move the $x$ term to the right side, then multiply both sides by $e^{3t/10}$ :

$e^{3t/10}x'+\dfrac{3e^{t/10}}{10}x=15e^{3t/10}$

$\implies\left(e^{3t/10}x\right)'=15e^{3t/10}$

Integrate both sides, then solve for $x$ :

$e^{3t/10}x=50e^{3t/10}+C$

$\implies x(t)=50+Ce^{-3t/10}$

Since the tank starts with 5 g of salt at time $t=0$ , we have

$5=50+C\implies C=-45$

$\implies\boxed{x(t)=50-45e^{-3t/10}}$

The time it takes for the tank to hold 20 g of salt is $t$ such that

$20=50-45e^{-3t/10}\implies t=\dfrac{20}3\ln\dfrac32\approx2.7031\,\mathrm{min}$

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1 year ago

Rob borrows $15.00 from his father, and then he borrows $3.00 more. Drag numbers to write an equation using negative integers to

Paul [167]

Answer:

Rob owes his father=-$15-$3= -$18

Step-by-step explanation:

Rob borrows $15 first and then $3.

Since we have to use negative integers, so

-$15-$3= -$18

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1 year ago

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Which system of equations can be used to find the roots of the equation 4 x Superscript 5 Baseline minus 12 x Superscript 4 Base

ehidna [41]

Answer:

D. on Edg 2020

Step-by-step explanation:

You are welcome, I helped better than that other guy!!!

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1 year ago

If the egress rate for a stadium is 5,500 fans per hour and it takes fans about one-third less time for fans to exit a game as i

Marina CMI [18]

Answer:

1833 fans per hour

Step-by-step explanation:

Ingress is entering and Egress is exiting.

Since exiting time is 1/3rd less than entering time, we have 5500 people exiting, so ingessing would be 1/3rd that.

Thus,

Ingress Rate = 5500/3 = 1833.33

Rounding to whole number, we have 1833 fans per hour

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1 year ago

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