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2 years ago

8

Rylee took out a loan for $3600 at 13% interest, compounded annually. If she makes yearly payments of $460, will she ever pay of

f the loan?

2 answers:

Masja [62]2 years ago

5 0

No interest is 468 per year

elena55 [62]2 years ago

3 0

Given that Rylee took out a loan for $3600 at 13% interest.

Where interest is compounded annually.

Interest for 1 year = 13% of 3600 = 0.13*3600 = 468

Amount due after 1 year = Loan + interest = 3600+468 = 4068

Monthly payment = 460

So Amount to be paid after 1 year = 4068-460 = 3608

New due amount $3608 is more than the loan amount $3600

Which means loan will always remain due for his entire life.

Hence Rylee will never be able to pay off the loan.

Interest must be less than the monthly payment in order to pay off the loan.

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Barry also looks into the cost of repaying an easy access loan for $1000. The up-front cost of the loan is $3 for every $20 borr

natta225 [31]

Answer:

Barry has to pay back $1150

Step-by-step explanation:

We can set up an equation to help solve this problem

x is the amount he has to pay back

x=1000+3(1000/20)

1000/20 lets us know how many times he borrowed 20 dollars

x=1000+3(50)

x=1000+150

x=1150

Barry has to pay back $1150

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2 years ago

Toy train A crosses a pole after every 24seconds. Toy train B crosses the pole after every 30 seconds and toy train C crosses th

gizmo_the_mogwai [7]

Answer: 6 minutes

Step-by-step explanation:

From the question, Toy train A crosses a pole after every 24seconds while Toy train B crosses the pole after every 30 seconds and then toy train C crosses the pole after every 36 seconds. We are going to solve this by finding their lowest common multiple (LCM).

24 = 24, 48, 72, 96, 120, 144, 168, 192, 216, 240, 264, 288, 312, 336, 360.

30 = 30, 60, 90, 120, 150, 180, 210, 240, 270, 300, 360, 390

36 = 36, 72, 108, 144, 180, 216, 252, 288, 324, 360.

We can see that the lowest common multiple of 24, 30 and 36 is 360.

Since 60 seconds make 1 minute, this will be converted to minutes.

= 360/60

= 6 minutes.

They all cross the pole together after 6 minutes.

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2 years ago

If r is the midpoint of qs rs=2x-4, st= 4x-1 and rt = 8x-43 find qs

sammy [17]

Answer:

$QS=68\ units$

Step-by-step explanation:

step 1

Find the value of x

we know that

r is the midpoint of qs

so

QR=RS

QS=QR+RS------> QS=2RS -----> equation A

RT=RS+ST ----> equation B

see the attached figure to better understand the problem

Substitute the given values in the equation B and solve for x

$8x-43=(2x-4)+(4x-1)$

$8x-43=6x-5$

$8x-6x=43-5$

$2x=38$

$x=19$

step 2

Find the value of RS

$RS=2x-4$

substitute the value of x

$RS=2(19)-4$

$RS=34\ units$

step 3

Find the value of QS

Remember equation A

QS=2RS

so

$QS=2(34)=68\ units$

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2 years ago

10. APPLICATION Inspector 47 at the Zap battery plant

alexdok [17]

2010 47 +ten thousand split decide and

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2 years ago

A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h

julsineya [31]

Answer:

a. $P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

b. $E(x) = 0.3$

c. $S(x)=0.5196$

d. $E=5,000$

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

$P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\$

For binomial distribution:

$E(x)=np\\S(x)=\sqrt{np(1-p)}$

Therefore, the company can expect to win 0.3 bids and it is calculated as:

$E(x) = np = 3*0.1 = 0.3$

Additionally, the standard deviation of the number of bids won is:

$S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196$

Finally, the probability to won 1, 2 or 3 bids is equal to:

$P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001$

So, the expected profit for the company is equal to:

$E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000$

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

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2 years ago