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Sindrei [870]
2 years ago
10

A video game randomly chooses your car color and type. The probability of getting a red car is 0.20, and the probability of gett

ing a convertible is 0.40.
Event A = You get a red car.
Event B = You get a convertible.
A and B are independent events if _____.
A.The probability of getting a red car or a convertible is 0.60.
B.The probability of getting a red car or a convertible is 0.08.
C.The probability of getting a red convertible is 0
D.The probability of getting a red convertible is 0.08
Mathematics
1 answer:
pishuonlain [190]2 years ago
7 0

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

Event A: You get a red car

and

P(A)=0.20

Similarly,

Event B: You get a convertible

and

P(B)=0.40

So, if A and B are independent , then they must satisfy,

P(A).P(B)=P(A\cap B)

So,

P(A\cap B)=0.4\times 0.2=0.08

Hence, Option 'D' is correct, which states that the probability of getting a red convertible is 0.08.

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Answer:

39.3701 inches in a meter

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naveed makes 6.5litres of soup,correst to the nearest 0.5 litre he serves portions of his soup in 330ml cups correct to the near
Karolina [17]

Answer:

Number of Cups = 19

Step-by-step explanation:

Given

Size of Soup = 6.5 litres

SIze of cup = 330 ml

Required

Number of Cups.

First, it'll be assumed that the size of cups are uniform (the same).

The number of cups needed is calculated by dividing the size of soup by the size of the cup;

Number of Cup = Size of Soup/Size of Cup

Number of Cup = 6.5 litres/ 330 ml

<em>Convert units;</em>

<em>1 litres = 1000 ml</em>

<em>So,</em>

<em>6.5 litres = 6.5 * 1,000 ml</em>

<em>6.5 litres = 6,500 ml</em>

<em></em>

So,

Number of Cups = 6500 ml/330 ml

Number of Cups = 19.696969697

From the solution above, Naveed will definitely be able to serve 19 cups. The remaining fractional part won't fill a cup;

Hence, Number of Cups = 19

3 0
2 years ago
The owner of a toy store received a shipment of 1552 party favors came in 28 boxes the same number of party favors were in 27 of
klemol [59]

Answer : (13)

Let x be the number of party favors in each (27 boxes)

Let y be the number of favors in last box

Given : total of party favors = 1552

27 boxes + last box = 1552

27x + y = 1552

We divide 1552 by 27, the quotient will be our x and the remainder will be y(number of party favors in last box)

Use long division

= 57 and remainder is 13

the number of party favors in each of (27 boxes) = 57

the number of party favors in last box = 13

So, there are 13 party favors in last box.

Read more on Brainly.com - brainly.com/question/9624402#readmore

3 0
2 years ago
Charles has a collection of dimes and quarters worth $1.25. He has 8 coins. Write a systems of equations to represent this situa
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Answer:

* The systems of equations are:

# d + q = 8 ⇒ (1)

# 10d + 25q = 125 ⇒ (2)

Charles has 5 dimes and 3 quarters

Step-by-step explanation:

* Lets explain how to solve the problem

- Charles has a collection of dimes and quarters worth $1.25

- He has 8 coins

* To solve the problem remember that:

# 1 dim = 10 cents

# 1 quarter = 25 cents

# 1 dollar = 100 cents

- Assume that the number of dimes is d and the number of

 quarter is q

∵ Charles has 8 coins

- The number of dimes and the number of quarters equal the

  number of the coins

∴ d + q = 8 ⇒ (1)

∵ 1 dime = 10 cents

∴ The value of dimes = 10 × d = 10d

∵ 1 quarter = 25 cents

∴ The value of quarters = 25 × q = 25q

∵ The collection worth $1.25

∵ 1 dollar = 100 cents

∴ The collection worth = 1.25 × 100 = 125 cents

∴ 10d + 25q = 125 ⇒ (2)

* The systems of equations are:

# d + q = 8 ⇒ (1)

# 10d + 25q = 125 ⇒ (2)

* Lets solve the equations

- Multiply equation (1) by (-10) to eliminate d

∴ -10d + -10q = -80 ⇒ (3)

- Add equations (2) and (3)

∴ 15q = 45

- Divide both sides by 15

∴ q = 3

- Substitute the value of q in equation (1) to find the value of d

∴ d + 3 = 8

- Subtract 3 from both sides

∴ d = 5

∵ d represents the number of dimes and q represents the number

  of quarters

∴ Charles has 5 dimes and 3 quarters

4 0
2 years ago
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