Polygons ABCD and EFGH are similar. Find the length of EH?
1 answer:
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Answer:
Option (B)
Step-by-step explanation:
x² + x - 1) x³ + 6x² + 0x + 5 ( x + 5
- (<u>x³ + x² - x</u>)
5x² + x + 5
-(<u>5x² + 5x - 5)</u>
-4x + 10
Result :
By the comparing the result with the Lorie's solution,
She made a mistake in the last step in which she combined the constant incorrectly.
Therefore, Option (B) will be the answer.
Note necessary facts about isosceles triangle ABC:
- The median CD drawn to the base AB is also an altitude to tha base in isosceles triangle (CD⊥AB). This gives you that triangles ACD and BCD are congruent right triangles with hypotenuses AC and BC, respectively.
- The legs AB and BC of isosceles triangle ABC are congruent, AC=BC.
- Angles at the base AB are congruent, m∠A=m∠B=30°.
1. Consider right triangle ACD. The adjacent angle to the leg AD is 30°, so the hypotenuse AC is twice the opposite leg CD to the angle A.
AC=2CD.
2. Consider right triangle BCD. The adjacent angle to the leg BD is 30°, so the hypotenuse BC is twice the opposite leg CD to the angle B.
BC=2CD.
3. Find the perimeters of triangles ACD, BCD and ABC:
4. If sum of the perimeters of △ACD and △BCD is 20 cm more than the perimeter of △ABC, then
5. Since AC=BC=2CD, then the legs AC and BC of isosceles triangles have length 20 cm.
Answer: 20 cm.