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Anni [7]
2 years ago
7

Lorie is using long division to find the quotient of x^3 + 6x^2 + 5 and x^2 + x -1, as shown at the bottom of this question.

Mathematics
1 answer:
meriva2 years ago
7 0

Answer:

Option (B)

Step-by-step explanation:

x² + x - 1) x³ + 6x² + 0x + 5 ( x + 5

           - (<u>x³ +   x²  -  x</u>)

                      5x² + x + 5

                    -(<u>5x² + 5x - 5)</u>

                             -4x + 10

Result : x+5+\frac{-4x+10}{(x^{2}+x-1)}

By the comparing the result with the Lorie's solution,

She made a mistake in the last step in which she combined the constant incorrectly.

Therefore, Option (B) will be the answer.

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Let's find 1/2 - 1/6. First, write the subtraction so the fractions have denominator . Then subtract. 1/2 - 1/6 = blank/6 - 1/6
SOVA2 [1]

Step-by-step explanation:

1/2 - 1/6 = 3/6 - 1/6 = 2/6

Hope this helps!!!

7 0
2 years ago
Three boards are placed end to end to make a walkway. The first board is 4 feet 5 inches long, the second board is 6 feet 9 inch
Kazeer [188]

Answer:

15 feet and 1 inch long

Step-by-step explanation:

add up the feet: 4+6+3= 13 feet

add up the inches: 5+9+11 = 25 inches

25/12= 2 feet 1 inch

13 feet + 2 feet + 1 inch= 15 feet 1 inch

7 0
2 years ago
Thomas wants to invite Madeline to a party. He has an 80% chance of bumping into her at school. Otherwise, he’ll call her on the
Ivenika [448]

Answer:

84%

Step-by-step explanation:

The probability of Thomas bumping into her at school is 80%, so the probability of not bumping into her is 100% - 80% = 20%.

If he doesn't bump into her (20% chance), he will call her, and the probability of asking her in this case is 60%, so the final probability of asking her in this case is:

P_1 = 20\% * 60\% = 12\%

If he bumps into her (80% chance), the probability of asking her is 90%, so the final probability of asking her in this case is:

P_2 = 80\% * 90\% = 72\%

To find the probability of Thomas inviting Madeline to the party, we just have to sum the probabilities we found above:

P = P_1 + P_2

P = 12\% + 72\% = 84\%

5 0
2 years ago
A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly locat
DiKsa [7]

Answer:

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let \mu be the random variable that follows a Poisson distribution, then mean \mu = \dfrac{10}{500}= 0.02

and the mean that the random selection of 50 pages will contain no error is \lambda = 50 \times 0.02 =1

∴

Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}

Pr(q =0) = 0.368

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )]    since it is less than 2

P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]

P(X \geq 2) = 1 - [0.3678 +0.3678]

P(X \geq 2) = 1 -0.7356

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

6 0
2 years ago
Alan, Bill, and Calvin are playing a game with collectible cards. At the moment, Alan has 11 less than 2 1/2 times the number of
kramer
Bill has 12 cards. I figured this out by making a table and drawing an equation: 

7 0
2 years ago
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