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Nostrana [21]
2 years ago
15

Emma's square patio below has been area=31 sq ft. She decides to decrease one dimension by 1 foot and decreases the other dimens

ion by 4 feet. DO NOT USE DECIMAL APPROXIMATIONS. What are the dimensions? ​
Mathematics
1 answer:
Andreas93 [3]2 years ago
5 0

Answer:

4.57ft  by 1.57 ft

Step-by-step explanation:

We are given that

Emma's square patio has been area=31 sq.ft

One dimension decrease by 1 foot and other dimension decrease by 4 feet.

We have to find the new dimensions of Emma's patio.

Let x be the side of Emma's square patio

We know that

Area of square=x^2

x^2=31

x=\sqrt{31}=5.57 ft

One dimension=5.57-1=4.57 ft

other dimension=5.57-4=1.57 ft

Hence, the new dimension of Emma's patio is given by

4.57ft  by 1.57 ft

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Answer: 4

Step-by-step explanation:

Let N be the total number of runs.

The microscopes per year will be equal to the total number of runs * microscopes per run

total number of microscopes = total number of runs * microscopes per run

now we have each run to cost 2500, therefore:

run costs = 2500 * total runs = 2500*N

we also have insurance and storage costs (note the average thats why we divide by 2):

storage costs = 20* microscopes per run /2 = 20*N/2

insurance costs = 15 * microscopes per run = 15*N

the costs are:

costs = run costs + storage + insurance

now the comany sells 1600 microscopes a year, so in order to figure out the number of microscopes per run we divide 1600 by the total number of runs N and replace in the costs

costs = 2500N + 40000/N => C(N) = 2500N + 40000/N

now derivate the function with respect to N and equal to 0:

\frac{d}{dN}(2500N + 40000/N) = 2500(1-16/N^2) \\\\  2500(1-16/N^2) = 0\\

this gives you two solutions, N = -4 which is not eligible (you cant make negative microscopes lol) and N = 4 which is the answer

have a nice day

4 0
2 years ago
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
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so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
2 years ago
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Answer:

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Step-by-step explanation:

The only Pythagorean identities are:

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2. \ 1+Tan^2\theta=Sec^2\theta

3. \ 1+Cot^2\theta=Csc^2\theta

4. \ Sin^2\theta=1-Cos^2\theta\\  \ \ Cos^2\theta=1-Sin^2\theta

 

Therefore,Cot^2\theta-Csc^2\theta=-1 is correct as it's one of the pythagorean identities.

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Answer:

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Step-by-step explanation:

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If he doesn't bump into her (20% chance), he will call her, and the probability of asking her in this case is 60%, so the final probability of asking her in this case is:

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If he bumps into her (80% chance), the probability of asking her is 90%, so the final probability of asking her in this case is:

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P = P_1 + P_2

P = 12\% + 72\% = 84\%

5 0
2 years ago
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