Refer to the following data: Period Demand 1 58 2 59 3 60 4 61 What is the last-value forecast for the next period?

MrRa [10]

3+5.2x=1-2.8x

1. 3+5.2x+2.8x=1

2. 5.2x+2.8x=1-3

5.2x+2.8x=1-3

1. 8x=1-3

2. 8x=-2

8x=-2

1. =-(1/4)

Alternative form:

2. x=-0.25

5 0

2 years ago

Given: ΔABC, AC = BC, AB = 3 CD ⊥ AB, CD = √3 Find: AC

valina [46]

Answer:

$\boxed{AC = 2.3}$

Step-by-step explanation:

AD = BD (CD bisects AB means that it divides the line into two equal parts)

So,

AD = BD = AB/2

So,

AD = 3/2

AD = 1.5

<u><em>Now, Finding AC using Pythagorean Theorem:</em></u>

$c^2 = a^2+b^2$

Where c is hypotenuse (AC), a is base (AD) and b is perpendicular (CD)

$AC^2= (1.5)^2+(\sqrt{3} )^2$

$AC^2 = 2.25 + 3$

$AC^2 = 5.25$

Taking sqrt on both sides

$AC = 2.3$

3 0

2 years ago

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Two functions are graphed on the coordinate plane. On a coordinate plane, a curved line with an upward arc, labeled g of x, cros

n200080 [17]

Answer:

(B) f(-4)=g(-4) and f(0)=g(0)

Step-by-step explanation:

From the given graph, the lines f(x) and g(x) intersects at two different points.

When x=-4, f(-4)=4 and g(-4)=4
When x=0, f(0)=4 and g(0)=4

Therefore, the points which represent where f(x)=g(x) are:

f(-4)=g(-4); and
f(0)=g(0)

The correct option is B.

5 0

2 years ago

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You want to test the effects of water aerobics on resting heart rate. You decide to test two different levels of exercise (water

DochEvi [55]

Answer:

The correct option is;

A). Randomized block design

Step-by-step explanation:

In a randomized block design the experimental units or subjects of the experiment are separated into subgroups known as blocks with the property that the the variability (difference) of the parameters within the blocks are lesser than the variability between block, such that the treatment of the research or experiment are assigned differently to each block

The groups can therefore comprise of the following;

Group 1

15 men and 15 women to perform water aerobics for 30 minutes twice a week

Group 2

15 men and 15 women to perform water aerobics for 60 minutes once a week

Therefore, the effect of the experiment will be much less attributed to gender than to the durations of the water aerobic exercise.

5 0

2 years ago

A liquid dietary product implies in its advertising that use of the product for one month results in an average weight loss of a

BigorU [14]

Answer:

Following are the responses to the given question:

Step-by-step explanation:

Please find the table in the attached file.

mean and standard deviation difference: $\bar{d}=\frac{\Sigma d}{n} =\frac{-4-6-.......-4-4}{8}=-4.125 \\\\S_d=\sqrt{\frac{\Sigma (d-\bar{d})^2 }{n-1}}=\sqrt{\frac{(-4 + 4.125)^2 +.......+(-4 +4.125)^2 }{8-1}}= 1.246$

For point a:

hypotheses are:

$H_0 : \mu_d \geq -3\\\\H_a : \mu_d < -3\\\\$

degree of freedom:

$df=n-1=8-1=7$

From t table, at $\alpha = 0.05$ , reject null hypothesis if $t$ .

test statistic:

$t=\frac{\bar{d}-\mu_d }{\frac{s_d}{\sqrt{d}}}=\frac{ -4.125- (-3)}{\frac{1.246}{ \sqrt{8}}} =-2.55$

because the $t=-2.553$ , removing the null assumption. Data promotes a food product manufacturer's assertion with a likelihood of Type 1 error of 0.05.

For point b:

From t table, at $\alpha =0.01$ , removing the null hypothesis if $t$ .

because $t=-2.553 >-2.908$ , fail to removing the null hypothesis.

The data do not help the foodstuff producer's point with the likelihood of a .01-type mistake.

For point c:

Hypotheses are:

$H_0: \mu_d \geq -5\\\\H_a: \mu_d < -5$

Degree of freedom:

$df=n-1=8-1=7$

From t table, at $\alpha =0.05$ , removing the null hypothesis if $t$ .

test statistic: $t=\frac{\bar{d}-\mu_d}{\frac{s_d}{\sqrt{n}}} =\frac{-4.125-(-5)}{\frac{1.246}{\sqrt{8}}}=1.986$

Since $t-1.986 >-1.895$ , The null hypothesis fails to reject. The results do not support the packaged food producer's claim with a Type 1 error probability of 0,05.

From t table, at $\alpha= 0.01$ , reject null hypothesis if $t$ .

Since $t=1.986>-2.998$ , fail to reject null hypothesis.

Data do not support the claim of the producer of the dietary product with the probability of Type 1 error of .01.

5 0

2 years ago