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Finger [1]
2 years ago
12

A rectangular prism has a length of 4.2 cm, a width of 5.8 cm, and a height of 9.6 cm. A similar prism has a length of 14.7 cm,

a width of 20.3 cm, and a height of 33.6 cm. The dimensions of the smaller prism are each multiplied by what factor to produce the corresponding dimensions of the larger prism? 3 4 4 5
Mathematics
2 answers:
grigory [225]2 years ago
5 0

Answer: 3.5

Step-by-step explanation:

Given: Dimensions of larger prism = length of  4.2 cm, a width of 5.8 cm, and a height of 9.6 cm.

Dimensions of smaller prism = length of 14.7 cm, a width of 20.3 cm, and a height of 33.6 cm.

Scale factor = \dfrac{\text{Size of image}}{\text{Size of original figure}}

Since, smaller figure is the original figure and the bigger one is the image.

So, scale factor = \dfrac{14.7}{4.2}=3.5  [Taking lengths

Hence, the factor to produce the corresponding dimensions of the larger prism = 3.5

Radda [10]2 years ago
3 0

Answer:

3.5

Step-by-step explanation:

i said its 3.5

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A coin has a radius of 10 mm. How long will it take the coin to roll through the given angle measure at the given angular veloci
Gemiola [76]

Answer:

t = 1.57 sec

distance, d = 98.65 mm

Step-by-step explanation:

Given an angle of 540°

At 6 revolutions per second, which is the angular velocity.

Radius, r = 10 mm

We are asked to find the time and the distance.

To find the time, let's use the formula:

\theta = a*t

Where \theta = angle in radians.

Converting 540° to radians, we have:

\theta = 540 * \frac{\pi}{180} = 9.42 rad

Therefore, from the formula, let's find t.

\theta = a*t

9.42 = 6 * t

t = \frac{9.42}{6} = 1.57

time = 1.57

To find the distance, we have:

\frac{1.57 * 360}{360} = \frac{d}{2 \pi r}

\frac{1.57 * 360}{360} = \frac{d}{2\pi 10}

1.57 = \frac{d}{20\pi}

d = 20 \pi *1.57

d = 98.65 mm

Therefore, the time is 1.57 seconds and the distance is 98.65 mm

8 0
2 years ago
What is the ratio of the area of sector ABC to the area of sector DBE?
shusha [124]

We have to find the" ratio of the area of sector ABC to the area of sector DBE".

Now,

the general formula for the area of sector is

Area of sector= 1/2 r²θ

where r is the radius and θ is the central angle in radian.


180°= π rad

1° = π/180 rad


For sector ABC, area= 1/2 (2r)²(β°)

= 1/2 *4r²*(π/180 β)

= 2r²(π/180 β)

For sector DBE, area= 1/2 (r)²(3β°)

= 1/2 *r²*3(π/180 β)

= 3/2 r²(π/180 β)

Now ratio,

Area of sector ABC/Area of sector DBE =\frac{2r^{2}*\ \frac{\pi}{180} beta}{3/2 r^{2}*\ \frac{\pi}{180}beta}

= 4/3

7 0
2 years ago
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A softball pitcher throws a softball to a catcher behind home plate. The softball is 3 feet above the ground when it leaves the
Xelga [282]

The <em><u>correct answer</u></em> is:

h(t) = –16t² + 50t + 3

Explanation:

The general form of an equation such as this is h(t) = at² + v₀t + h₀, where a is the constant due to gravity, v₀ is the initial velocity and h₀ is the initial height.

We are given that the constant due to gravity is -16.

The initial velocity is 50, and the initial height is 3; this gives us the equation

h(t) = -16t² + 50t + 3

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2 years ago
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Jake went on a riverboat tour. After returning from the tour, he was curious to know the speed at which the boat was going. Duri
atroni [7]
I'm sorry I'm too lazy to read all of that. However, I did get the main point. The river was going at 3 mph. Since he wanted to travel 10 miles upstream and downstream, you would have to subtract 20 by 3. This would mean he was going at a speed of 17 mph. 
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2 years ago
Every day, Jorge buys a lottery ticket. Each ticket has a probability of of winning a prize. After six days, what is the probabi
Romashka [77]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.

Answer:

The probability that Jorge has won at least one prize after six days is

P(at least 1 win) = 0.6487

Step-by-step explanation:

Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.

We want to find out the probability that Jorge has won at least one prize after six days.

P(at least 1 win) = 1 - P(not winning for 6 days)

We know that the probability of winning is 0.16 then the probability of not winning is

P(not winning) = 1 - 0.16 = 0.84

For 6 days,

P(not winning for 6 days) = 0.84×0.84×0.84×0.84×0.84×0.84

P(not winning for 6 days) = 0.84⁶

P(not winning for 6 days) = 0.3513

Finally,

P(at least 1 win) = 1 - P(not winning for 6 days)

P(at least 1 win) = 1 - 0.3513

P(at least 1 win) = 0.6487

6 0
2 years ago
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