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AveGali [126]
2 years ago
13

A pair of events are observed to have coordinates (0s,0m) and (50.0s,9.00×109m) in a frame s. what is the proper time interval δ

τ between the two events?
Mathematics
1 answer:
Ludmilka [50]2 years ago
5 0
To find out time interval δt we need to substract initial time from the final time. In this question first number in the coordinates representes time:

δt=50 - 0
δt= 50s

TIme interval is 50s.
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Hello IdontKnowHowToMath,

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Solving our equation:
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The total amount accrued, principal plus interest, from simple interest on a principal of $6,000.00 at a rate of 3% per year for 4 years is $6,720.00.
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Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal
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Answer:

0.0359

Step-by-step explanation:

Data provided:

mean values of three independent times are 15, 30, and 20 minutes

the standard deviations are 2, 1, and 1.6 minutes

Now,

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or

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therefore,

Standard deviation = √variance

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Standard deviation =  2.75

Thus,

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Z-value = - 1.81

from the Z-table

the Probability of Z ≤ -1.81 = 0.0359

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Pani-rosa [81]

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Step-by-step explanation:

Since the printer depreciates at a rate of 5% per year, I believe the stated equation is miss typed. Therefore I'll answer this with the correct equation that would represent that setting:

y(x) = 25,000*0.95^x

In the first year the value of the printer is:

y(1) = 25,000*0.95^1 = 23,750

On the second year the value of the printer is:

y(2) = 25,000*0.95^2 = 22,562.5\\

On the third year the value of the printer is:

y(3) = 25,000*0.95^3 = 21,434.38\\

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

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