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AveGali [126]
2 years ago
13

A pair of events are observed to have coordinates (0s,0m) and (50.0s,9.00×109m) in a frame s. what is the proper time interval δ

τ between the two events?
Mathematics
1 answer:
Ludmilka [50]2 years ago
5 0
To find out time interval δt we need to substract initial time from the final time. In this question first number in the coordinates representes time:

δt=50 - 0
δt= 50s

TIme interval is 50s.
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Answer:

Step-by-step explanation:

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After two-years

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After three years

A=p(1+r/n)^nt

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=$2394.063

8 0
2 years ago
What is the answer to the problem 44.84 x 9.84?
Marta_Voda [28]
I hope this helps you

7 0
2 years ago
Which expression shows the amount of tax on a T-shirt that costs x dollars, if tax is 7%?
alina1380 [7]

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Step-by-step explanation:

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2 years ago
Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your methods as well
laiz [17]

Answer:

The  value is  P(A) =  0.133617

Step-by-step explanation:

From the question we are told that

  The  mean is  \mu =  7.5

  The standard deviation is  \sigma  =  0.2

  The safest water level is  between  7.2 and  7.8

Generally the probability that the selected pool has a pH level that is not considered safe is mathematically represented as

       P(A) =  1 - P(7.2 \le X  \le 7.8 )

Here  

      P(7.2 < X  < 7.8 ) = P(\frac{ 7.2 - \mu }{\sigma } <  \frac{X - \mu }{ \sigma }

Generally \frac{X - \mu }{ \sigma } =  Z (The  \ standardized \  value  \  of  X )

So

 P(7.2 < X  < 7.8 ) = P(\frac{ 7.2 - 7.5 }{0.2 } < Z    

 P(7.2 < X  < 7.8 ) = P(-1.5 < Z  

=>  P(7.2 < X  < 7.8 ) = P(Z <  1.5) - P(  Z < - 1.5)

From the z-table the probability of  (Z <  -1.5) and   (  Z <1.5)  are

    P(Z <  1.5) =  0.93319

and  

    P(Z <  -1.5) =  0.066807

So

      P(7.2 < X  < 7.8 ) =0.93319 - 0.066807

       P(7.2 < X  < 7.8 ) =0.0866383

So

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=>  P(A) =  0.133617

5 0
2 years ago
Kayson mixes 300300300 milliliters (\text{mL})(mL)left parenthesis, start text, m, L, end text, right parenthesis of spinach, 20
Georgia [21]

Answer:

Total, T = (300s+200b+42d) mg

Step-by-step explanation:

Given that,

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There are s mg of vitamin C per mL of spinach, b mg per mL of berries, and d mg per mL of dressing.

In 300 mL of spinach vitamin C is = (300 s)mg

In 200 mL of berries vitamin C is = (200 b)mg

In 42 mL of salad vitamin C is = (42 d)mg

It means that, total mg of vitamin C is :

Total, T = (300s+200b+42d) mg

Hence, this is the required solution.

4 0
2 years ago
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