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scoray [572]
2 years ago
5

I WILL GIVE BRAINLIEST Draw the line of reflection that reflects △ABC\triangle ABC△ABCtriangle, A, B, C onto △A′B′C′\triangle A'

B'C'△A′B′C′triangle, A, prime, B, prime, C, prime.

Mathematics
1 answer:
Bogdan [553]2 years ago
3 0

Answer:

See diagram attached.

Step-by-step explanation:

The line of reflection of preimage ABC reflected onto image A'B'C' can be found by the perpendicular bisector of lines joining the corresponding points of the image and preimage, for example, AA', or BB'.

See diagram attached.

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Steve is trying to increase his average pace per mile by running hills. The hill on 1st Avenue rises 3 vertical feet for each ho
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1st Avenue would be more difficult because it’s rise and run is for every one foot forward it is 3 feet up. Meanwhile avenue 16th would start at (3,1) and the rise and run would be for every 3 feet it would go up 1 foot.
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Eighteen 2.5 gallon buckets are needed to fill a cistern with water. Find the constant of variation. Please help! Thank you!
Allushta [10]

Given:

Eighteen 2.5 gallon buckets are needed to fill a cistern with water.

To find:

The constant of variation.

Solution:

If y is directly proportional to x, then

y\propto x

y=kx

Where, k is constant of variation.

In the given problem, water in cistern (w) is directly proportional to number of buckets (n).

w\propto n

w=2.5n        (Capacity of each bucket is 2.5 gallons)

Therefore, the constant of variation is 2.5.

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1 year ago
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An angle t is drawn from the center of the unit circle. Find a formula in terms of t for the straight line distance d between th
Doss [256]

Answer:

d = \sqrt{2}\cdot \sqrt {1-\cos t - \sin t}

Step-by-step explanation:

Let suppose that one of the radii meets the circle at the point (1,0). The straight line distance formula is:

d = \sqrt{(\cos t - 1)^{2}+(\sin t - 1)^{2}}

d = \sqrt{(\cos^{2}t - 2\cdot \cos t + 1)+(\sin^{2}t - 2\cdot \sin t + 1)}

d = \sqrt{2-2\cdot (\cos t + \sin t )}

d = \sqrt{2}\cdot \sqrt {1-\cos t - \sin t}

5 0
2 years ago
Which of the following is an example of a null hypothesis? A. The average quantity of detergent put into a box by this filling m
gavmur [86]

Answer:

C

Step-by-step explanation:

Null hypothesis: hypthesis to test that there is no significant difference between the specific characteristic of a population. Analysts look to reject a null hypothesis

A. the shipping company's average delivery time is different from 3 days. This is an example of alternative hypothesis. Null hypothesis is writtien as a claim

B. This again is an example of alternate hypthesis. The claim that mean is 0.03 is rejected with the results

C. This is a claim

D. This is rejection of a claim that mean is 1 pound

E. This is rejection of claim that average delivery time is 3 days.

5 0
2 years ago
The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of
slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

5 0
2 years ago
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