Answer:
Step-by-step explanation:
Hello!
You need to construct a 95% CI for the population mean of the length of engineering conferences.
The variable has a normal distribution.
The information given is:
n= 84
x[bar]= 3.94
δ= 1.28
The formula for the Confidence interval is:
x[bar]±
*(δ/n)
Lower bound(Lb): 3.698
Upper bound(Ub): 4.182
Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242
I hope it helps!
Answer: C. Significant at 0.036
Step-by-step explanation:
Given:
Number of selected samples Ns= 500
Number of airplane that arrive on time Na = 482.
Number of airplane that arrive late Nl = 500 - 482 = 18
The probability that an airplane arrive late:
P(L) = Nl/Ns
P(L) = 18/500
P(L) = 0.036
Interpret an event as significant if its probability is less than or equal to 0.05.
Since P(L) < 0.05
P(L) = Significant at 0.036
Looking at the table, we can readily say that the correct
answer to this question is:
<span>
“With
increasing elapsed time, the amount of dissolved chlorine increases.”</span>
<span>
The
amount dissolved always increases with time unless it has already reached the
maximum limit. </span>
The height of the lighthouse is :
h = 14 ft ( same as the distance from Kelly to a lighthouse ).
tan y = 14 / ( 14 + 12 ) = 14 / 26 = 0.5384615
y = tan^(-1) 0.5384615 = 28.3°
Answer: y = 28.3°