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gladu [14]
2 years ago
15

Given the graph below, find GH.

Mathematics
1 answer:
Alex777 [14]2 years ago
3 0

Answer:

GH = 6.3 (nearest tenth)

Step-by-step explanation:

Given:

G(-2, -3)

H(0, 3)

Required:

Distance between point G and H = GH

Solution:

Distance between G(-2, -3) and H(0, 3):

GH = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

G(-2, -3) = (x_1, y_1)

H(0, 3) = (x_2, y_2)

GH = \sqrt{(0 - (-2))^2 + (3 - (-3))^2}

GH = \sqrt{(2)^2 + (6)^2}

GH = \sqrt{4 + 36} = \sqrt{40}

GH = 6.3 (nearest tenth)

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a building security code has 2 numeric digits 0 through 9 followed by 2 letters. what is the probability that the first digit is
sleet_krkn [62]

If we remove human choices in creating the code the answer is 10 (the possible choices) times 26 (the possible choices) so 260 is the probability

7 0
2 years ago
Read 2 more answers
At a particular restaurant, each onion ring has 45 calories and each slider has 325 calories. A combination meal with onion ring
AlladinOne [14]

Answer:

There were 6 onion rings and 2 slider in the combination meal.

Step-by-step explanation:

Let x be the number of onion rings and y be the number of slider.

Calories in one onion ring = 45 calories

Calories in one slider = 325 calories

Total number of calories = 920

Thus, we can write the equation:

45x + 325y = 920

There are 3 times as many onion rings as the sliders.

Thus, we can write the equation:

x = 3y

Solving the two equation by substitution method, we get,

45(3y) + 325y = 920\\460y = 920\\y = 2\\x = 3y = 3(2) = 6

Thus, there were 6 onion rings and 2 slider in the combination meal.

7 0
2 years ago
the price of a pack of gum today is 63 cents. this is 3 cents more than three times the price ten years ago. what was the price
Paul [167]
The answer would be .43 
7 0
1 year ago
Read 2 more answers
The distribution of heights of a certain breed of terrier has a mean of 72 centimeters and a standard de- viation of 10 centimet
RSB [31]

Answer:

Pr(X-Y ≤ 44.2) = 0.5593

Step-by-step explanation:

for a certain breed of terrier

Mean(μ) = 72cm

Standard deviation (σ) = 10cm

n = 64

For a certain breed of poodle

Mean(μ) = 28cm

Standard deviation (σ) = 5cm

n = 100

Let X be the random variable for the height of a certain breed of terrier

Let Y be the random variable for the height of a certain breed of poodle

μx - μy = 72 -28

= 44

σx - σy = √(σx^2/nx + σy^2/ny)

= √10^2/64 + 5^2/100

= √100/64 + 25/100

= √ 1.8125

= 1.346

Using normal distribution,

Z= (X-Y- μx-y) / σx-y

Z= (44.2 - 44) / 1.346

Z= 0.2/1.346

Z= 0.1486

From the Z table, Z = 0.149 = 0.0593

Φ(z) = 0 0593

The probability that the difference of the observed sample mean is at most 44.3 is Pr(Z ≤ 44.2)

Recall that if Z is positive,

Pr(Z≤a) = 0.5 + Φ(z)

Pr(Z ≤ 44.2) = 0.5 + 0.0593

= 0.5593

Therefore,

Pr(X-Y ≤ 44.2) = 0.5593

5 0
1 year ago
(-4k^4 + 14 + 3k^2) + (-3k^4 - 14k^2 -8)
tatyana61 [14]

Answer:

look at the picture above

6 0
2 years ago
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