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2 years ago

Find a solution to the linear equation y=8x−32 by filling in the boxes with a valid value of x and y.

Mathematics

2 answers:

mario62 [17]2 years ago

5 0

Answer:

Answers are below

Step-by-step explanation:

I made a table with some of the possible values for x and y.

I also graphed the equation to show the points on a graph.

If these answers are correct, please make me Brainliest!

malfutka [58]2 years ago

5 0

Answer:

Step-by-step explanation:

Arbitrarily choose x = 2. Then y = 8(2) - 32, or y = 16 - 32, or y = -16.

Thus, (2, -16) is one of an infinite number of solutions of y = 8x - 32.

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Which mathematical statement matches the vector operation shown in the geometric representation?

Sunny_sXe [5.5K]

Answer:

First Option $v+w = u$

Step-by-step explanation:

To graphically add two vectors a and b using the -tail and tip-method, you must draw the tail of b at the tip of the vector a. Then you must draw a line that goes from the tail of a to the tip of b. This line represents the sum of $a + b$ .

In this problem, notice that the tail of the vector w is on the tip of the vector v. The line that joins the tail of v with the tip of w is u.

Therefore we can say that $v + w = u$ .

The answer is the first option

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2 years ago

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Amalie wants to know if students in her class prefer hot dogs or hamburgers. Why should Amalie survey the entire population rath

hram777 [196]

It would be bias if Amalie just surveyed a small population of her class rather than the whole. Hope this helps!

8 1

2 years ago

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A........ divides a two - dimensional shape into two congruent shapes

weeeeeb [17]

Answer:

A diagonal. (A rectangle is divided into two triangles by a diagonal, for example.)

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2 years ago

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Alexis has a rectangular piece of red paper that is 4 centimeters wide. It’s length is twice it’s width. She glued a rectangular

Montano1993 [528]

for the rectangular red paper :

w₁ = width of the red paper = 4 cm

L₁ = length of red paper = 2 w = 2 x 4 = 8 cm

A₁ = area of the red paper = L₁ w₁ = 8 x 4 = 32 cm²

for the rectangular blue paper :

w₂ = width of the blue paper = 3 cm

L₂ = length of blue paper = 7 cm

A₂ = area of the blue paper = L₂ w₂ = 7 x 3 = 21 cm²

area visible is given as

A = A₁ - A₂ = 32 cm² - 21 cm² = 11 cm²

so 11 square units of red paper will be visible on top

5 0

2 years ago

Assume that a fair die is rolled. The sample space is , 1, 2, 3, 4, 56, and all the outcomes are equally likely. Find P8. Expres

liraira [26]

Answer:

$P\left(8\right)=0$

Step-by-step explanation:

Assuming that a fair die is rolled.

The sample space is 1, 2, 3, 4, 5, 6 and all the outcomes are equally likely.

Let X be the set of all possible outcomes. Let A be an outcome.

So, the probability that A occurs is:

$P\left(A\right)=\frac{|A|}{|X|}$

As the set of all possible outcomes of the roll of a single die is:

$X=\left\{1,2,3,4,5,6\right\}$

Observe that

$|X|=6$

Here

$|A|=0$ because 8 is not in the set sample space. So, the outcome of occurring the number 8 is not possible from the all possible outcomes.

So, the probability must be zero.

In other words,

$P\left(A\right)=\frac{|A|}{|X|}$

$P\left(8\right)=\frac{0}{6}=0$

Therefore,

$P\left(8\right)=0$

5 0

2 years ago