The longest length of dowel will feet in the dimension that will give us the highest length of the hypotenuse;
given that the dimension of our box is:
15 by 20 by 30:
this will be given by:
c^2=a^2+b^2+c^2
c^2=15^2+20^2+30^2
c^2=225+400+900
c^2=1525
c=√1525
c=39.05 cm
Therefore the longest dowel will be 39 cm (to the nearest whole centimeter)<span />
Answer:
D. 0.1353
B. 0.0473
Step-by-step explanation:
For an exponentially distributed random variable, the cumulative distribution function is:

with parameter λ=2, then P(X≥1) is equal to:

D. 0.1353
with parameter λ=1.5, then P(2≤X≤4) is equal to
B. 0.0473
Answer: 6.824%
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I'll have to know what the measurements of the containers. If it is in liters, then you would just use the container with the capacity of 9 liters.
Hope this helped :)
-H
Answer:
The probability that the whole package is uppgraded in less then 12 minutes is 0,1271
Step-by-step explanation:
The mean distribution for the length of the installation (in seconds) of the programs will be denoted by X. Using the Central Limit Theorem, we can assume that X is normal (it will be pretty close). The mean of X is 15 and the variance is 15, hence, the standard deviation is √15 = 3.873.
We want to find the probability that the full installation process takes less than 12 minutes = 720 seconds. Then, in average, each program should take less than 720/68 = 10.5882 seconds to install. Hence, we want to find the probability of X being less than 10.5882. For that, we will take W, the standariation of X, given by the following formula

We will work with
, the cummulative distribution function of the standard Normal variable W. The values of
can be found in the attached file.

Since the density function of a standard normal random variable is symmetrical, then 
Therefore, the probability that the whole package is uppgraded in less then 12 minutes is 0,1271.