So taking this as if there are 13 dozens of cookies. First we do 13 times 12 which would be 156 cookies in total. Then 156 cookies times 2.08 is 324.48
Answer:
4 CUPS OF SUNFLOWER SEEDS for the larger batch
Step-by-step explanation:
From the small batch:
2 cups of peanuts= 1 cup of sunflower seeds
Since the ratios are thesame, it therefore means that the proportion will be thesame.
For the large batch:
8 cups of peanuts = X cups of sunflower seeds.
Mathematically, let's express it as:
Let p = cups of peanuts
S= cups of sunflower seeds
X = unknown number of sunflower seeds
Therefore, connecting equation is:
2P = 1S
8P = X's
Cross Multiply to solve for X
X's * 2P = 1S * 8P
2PX = 8P
X = 8P / 2P
It therefore means that there'll be a need of:
4 CUPS OF SUNFLOWER SEEDS for the larger batch
<u>Part a)</u> if a page is reduced to 80%, what percent enlargement is needed to return it to its original size?
Let
x---------> the percent enlargement
we know that
the original size is the 100%
so
x*80%=100%
x=(100%/80%)
x=1.25--------> 1.25=(125/100)=125%
therefore
<u>the answer Part a) is</u>
the percent enlargement is 125%
<u>Part b)</u> Estimate the number of times in succession that a page must be copied to make the final copy less than 15% of the size of the original
we know that
A photocopy machine can reduce copies to 80% of their original size
so
Copy N 1
0.80*100%=80%
Copy N 2
0.80*80%=64%
Copy N 3
0.80*64%=51.2%
Copy N 4
0.80*51.2%=40.96%
Copy N 5
0.80*40.96%=32.77%
Copy N 6
0.80*32.77%=26.21%
Copy N 7
0.80*26.21%=20.97%
Copy N 8
0.80*20.97%=16.78%
Copy N 9
0.80*16.78%=13.42%-------------> 13.42% < 15%
therefore
<u>the answer Part b) is</u>
the number of times in succession is 9
Given that:
mean,μ=35.6 min
std deviation,σ=10.3 min
we are required to find the value of x such that 22.96% of the 60 days have a travel time that is at least x.
using z-table, the z-score that will give us 0.2296 is:-1.99
therefore:
z-score is given by:
(x-μ)/σ
hence:
-1.99=(x-35.6)/10.3
-20.497=x-35.6
x=35.6-20.497
x=15.103
During her pre-college years, Elise won 30% of the swim races she entered. During college, Elise won 20% of the swim races she entered. We can conclude that, in high school and college combined, Elise won <span>more than 20% but less than 30% of the races she entered</span>
