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juin [17]
2 years ago
12

Solve the following addition and subtraction problems. a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam b. 5 sq.km 95 ha 8,994 sq.m + 11 sq.

km. 11 ha 9,010 sq. m. c. 44 m – 5 dm d. 73 km 47 hm 2 dam - 11 km 55 hm
Mathematics
1 answer:
kipiarov [429]2 years ago
5 0
As a general rule to solve the problem we are going to transform all values to the lower unit.  
a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam
  3,000 m 900 m 90 m 19 m + 7,000 m 70 m = 4,009 + 7,070 = 11,079 m 
  b. 5 sq.km 95 ha 8,994 sq.m + 11 sq. km. 11 ha 9,010 sq. m.
  5,000,000 sq m 95,0000 sq m 8,994 sq m + 11,000,000 sq m 110,000 sq
9,010 sq m
  5,103,994 sq m + 11,119,010 sq m = 16,223,004 sq m 
 c. 44 m – 5 dm
  44 m - 0.5 m = 43.5 m 
 d. 73 km 47 hm 2 dam - 11 km 55 hm

  73,000 m 4,700 m 20 m - 11,000 m 5,500 m 
77,720 m - 16,500 m = 61,220 m
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The owner of a manufacturing plant employs eighty people. As part of their personnel file, she asked each one to record to the n
wariber [46]

Answer:

<em>Mean of the sample = 27.83</em>

<em> The variance of the the sample = 106.96</em>

<em> </em><em>Standard deviation of the sample = 10.34</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given random sample of six employees

x     26    32    29    16     45    19

mean of the sample

x^{-} = \frac{26+32+29+16+45+19}{6} = 27.83

Mean of the given data = 27.83

<u>Step(ii):-</u>

<u>Given data</u>

x           :       26         32           29           16           45        19

x - x⁻     :      -1.83      4.17        1.17       -11.83     17.17    -8.83

(x - x⁻)²  :    3.3489   17.3889   1.3689   139.9489  294.80 77.9689

∑ (x-x⁻)²  =   534.8245

Given sample size 'n' =6

The variance of given data

           S²  = ∑(x-x⁻)² / n-1  

           S^{2}  = \frac{534.8245}{6-1} = 106.9649

The variance of the given sample = 106.9649

<u> Step(iii):-</u>

Standard deviation of the given data

S = \sqrt{variance} = \sqrt{106.9649} =10.3423

Standard deviation of the sample = 10.3423

8 0
2 years ago
The article "Expectation Analysis of the Probability of Failure for Water Supply Pipes"† proposed using the Poisson distribution
oksian1 [2.3K]

Answer:

a. P(X ≤ 5) = 0.999

b. P(X > λ+λ) = P(X > 2) = 0.080

Step-by-step explanation:

We model this randome variable with a Poisson distribution, with parameter λ=1.

We have to calculate, using this distribution, P(X ≤ 5).

The probability of k pipeline failures can be calculated with the following equation:

P(k)=\lambda^{k} \cdot e^{-\lambda}/k!=1^{k} \cdot e^{-1}/k!=e^{-1}/k!

Then, we can calculate P(X ≤ 5) as:

P(X\leq5)=P(0)+P(1)+P(2)+P(4)+P(5)\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\P(3)=1^{3} \cdot e^{-1}/3!=1*0.3679/6=0.061\\\\P(4)=1^{4} \cdot e^{-1}/4!=1*0.3679/24=0.015\\\\P(5)=1^{5} \cdot e^{-1}/5!=1*0.3679/120=0.003\\\\\\P(X\leq5)=0.368+0.368+0.184+0.061+0.015+0.003=0.999

The standard deviation of the Poisson deistribution is equal to its parameter λ=1, so the probability that X exceeds its mean value by more than one standard deviation (X>1+1=2) can be calculated as:

P(X>2)=1-(P(0)+P(1)+P(2))\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\\\P(X>2)=1-(0.368+0.368+0.184)=1-0.920=0.080

4 0
2 years ago
Within the United States, approximately 11.25% of the population is left-handed. Of the males, 12.6% are left-handed, compared t
GuDViN [60]

Answer:

There is a 45.05% probability that the selected person is a right-handed female.

Step-by-step explanation:

We have these following probabilities

A 50% probability that a person is a male

A 50% probability that a person is a female.

A 12.6% probability that a male is left-handed.

A 9.9% probability that a female is left-handed.

If a person is selected at random, to find the probability that the selected person is a right-handed female, one would compute:

50% are female.

9.9% of the females are left-handed, so 100-9.9 = 90.1% of the females are right handed.

So

P = 0.5*0.901 = 0.4505

There is a 45.05% probability that the selected person is a right-handed female.

3 0
2 years ago
The Williams family wants to cover one wall in their living room with 1-foot square mirror tiles. The wall measures 8 feet by 10
ikadub [295]

Answer:80 mirror tiles will be needed to cover the wall is 80

Step-by-step explanation:

The dimension of one wall in living room is 8 feet by 10 feet. The wall is rectangular in shape. The area of a rectangle is expressed as

Length × width. The area of one wall in the living room would be

8 × 10 = 80 feet^2

The Williams family wants to cover one wall in their living room with 1-foot square mirror tiles.

The number of mirror tiles that they will need to cover the wall would be

80/1 = 80 mirror tiles.

3 0
2 years ago
If figure 1 is 3 then what is figure 100th
Alexxx [7]
A) 3x100= 300 since figure 1 is 3 then figure 100 is 3x100
8 0
2 years ago
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