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Firlakuza [10]
2 years ago
8

A research organization keeps track of what citizens think is the most important problem facing the country today. They randomly

sampled a number of people in 2003 and again in 2009 using a different random sample of people in 2009 than in 2003 and asked them to choose the most important problem facing the country today from the following​ choices, war,​ economy, health​ care, or other. Which of the following is the correct test to use to determine if the distribution of​ "problem facing this country​today" is different between the two different​ years?
A.

Use a​ chi-square test of homogeneity.

B.

Use a paired​ t-test.

C.

Use a​ two-sample z-test for proportions.

D.

Use a​ chi-square goodness-of-fit test.
Mathematics
1 answer:
Nuetrik [128]2 years ago
8 0

Answer:

Step-by-step explanation:

From the information given, the population is divided into sub groups. Each group would consist of citizens picking a particular choice as the most important problem facing the country. The choices are the different categories. In this case, the null hypothesis would state that the distribution of proportions for all categories is the same in each population. The alternative hypothesis would state that the distributions is different. Therefore, the correct test to use to determine if the distribution of​ "problem facing this country ​today" is different between the two different​ years is

A) Use a​ chi-square test of homogeneity.

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Answer:

He determined pounds per dollar by dividing 10 by 25 but wrote the unit rate as a dollar value.

Step-by-step explanation:

Given

\frac{10\ pounds}{\$25} = \frac{10\ pounds}{25} / \frac{\$25}{25} = \frac{0.4}{1}

Unit\ Price = 40\ cents

40\ cents * 6 = \$2.40

Required

Determine Ming's error

Ming's error is from here

\frac{10\ pounds}{\$25} = \frac{10\ pounds}{25} / \frac{\$25}{25} = \frac{0.4}{1}

He calculated the unit rate as pound per dollar.

So, after calculating the unit rate, the unit should be:

Unit\ Rate = 0.4\ pound/\$

But instead, he solved as:

Unit\ Rate = \$0.4/ pound

<em>Hence, (a) is correct</em>

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2 years ago
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What is the most precise name for quadrilateral ABCD with vertices A(-2,4), B(5,6), C(12,4) and D(5,2)?
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A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical
Korolek [52]

Answer:

78% probability that a randomly selected online customer does not live within 50 miles of a physical​ store.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Total outcomes:

100 customers

Desired outcomes:

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.

Using this​ estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical​ store?

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Answer:

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Step-by-step explanation:

The sum of angles of a triangle is always 180°.

Right angles are 90°, and obtuse angles are more than 90°. If each of the angles in the triangle is more than 0°, there obviously cannot be two angles that measure 90° or more. Just the sum of those two would be 180° or more, and that sum doesn't include the third angle.

So, any triangle can have at most one angle that is 90° or more (right or obtuse). The remaining two angles must be acute for the sum of angles to be 180°.

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Step-by-step explanation:

90 - 32 = 58

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