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Likurg_2 [28]
2 years ago
5

The graph of the function f(x) = (x + 2)(x + 6) is shown below.

Mathematics
2 answers:
iren [92.7K]2 years ago
4 0

Answer:

Step-by-step explanation:

f(x) = (x + 2)(x +6)

1) The function is positive for all real values of x where   x > –4 :

COUNTER-EXAMPLE : x =  - 3   you have -3>-4 but   (-3+2)(-3+6) = -1 ×3 =-3 no positive .

2) The function is positive for all real values of x where

x < –6 or x > –3.

COUNTER-EXAMPLE : x =  - 2.5   you have -2.5>-3 but   (-2.5+2)(-2.5+6) = -0.5 ×3.5 =-1.75 no positive .

same method for the statement : "The function is negative for all real values of x where

x < –2."

conclusion : statement about the function is true: "The function is negative for all real values of x where

–6 < x < –2."

.

Ne4ueva [31]2 years ago
4 0

Answer:

The function is negative for all real values of x where

–6 < x < –2

Step-by-step explanation:

 the function f(x) = (x + 2)(x + 6)  

LEts find the x intercept of the given function

0 = (x+2)(x+6)

x+2=0 so x=-2

x+6 = , so x=-6

x intercepts are -6  and -2

Lets draw a number line and use x intercepts and make 3 intervals

- infinity to -6     , -6 to -2 and -2 to infinity

LEts pick a number from each interval and check with f(x)

x<-6, pick -7

f(x) = (x + 2)(x + 6)  

f(-7)=(-7 + 2)(-7 + 6)  =5 , which is positive

–6 < x < –2, pick 4

f(-4)=(-4 + 2)(-4 + 6)  =-4 , which is negative

x>-2, pick 0

f(0)=(-0+ 2)(0 + 6)  =12 , which is positive

The function is negative for all real values of x where

–6 < x < –2

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PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab
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Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

m=\frac{y_2-y_1}{x_2-x_1}

The product of slopes of two perpendicular lines is -1.

Slope of GR is

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Slope of RT is

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If vertex T translated by rule

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(2,6)\rightarrow(2-1,6-2)

(2,6)\rightarrow(1,4)

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\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}

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Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

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