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Papessa [141]
2 years ago
12

The perimeter of a rectangular playing field is 244 feet. If its length is 2 feet longer than twice its width, what are the dime

nsions of the field?
Mathematics
2 answers:
ELEN [110]2 years ago
8 0
The perimeter (P) of a polygon is all the values of all the sides added together. (Length+Length+Width+Width) If the length (L) of the rectangle is 2 feet longer than twice the width (W), then L=2W+2. So now the perimeter is 2W+2+2W+2+W+W = P. This simplifies to 6W+4=P. If we know the perimeter is 244, then 6W+4=244. Then subtract four and divide by 6. W=40. If L=2W+2, then L=2(40)+2, or L=82. SO.....
The width is 40 feet
The length is 82 feet

klemol [59]2 years ago
6 0
Peri = 2A+2B 

<span>244 = 2(2+2x) + 2(x)</span>
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If the exclusion of Miss Jones and Mr Smith serving together was not present, the are 15C4 = 1365 ways of selecting the committee.
Miss Jones can serve on the committee in the following ways:
a) with 3 men
b) with 2 men and another woman
c) with 1 man and 2 other women
d) with 3 other women.
Arrangement d) obviously presents no restrictions.
Arrangement a) has 7C3 ways excluding Mr Smith, and 8C3 ways if Mr Smith was included.
Arrangement b) has 7C2 * 6 ways excluding Mr Smith, and 8C2 * 6 ways if Mr Smith was included.
Arrangement c) has 7 * 6C2 ways excluding Mr Smith, and 8 * 6C2 ways if Mr smith was included.
The reductions in ways caused by the restriction are as follows:
a) 8C3 - 7C3 = 21 ways
b) 6(8C2 - 7C2) = 42 ways
c) 6C2 = 15 ways
The total reduction in the number of ways is: 21 + 42 + 15 = 78.
Therefore the total number of ways of selecting the committee, while observing the restriction, is 1365 - 78 = 1287 ways.
4 0
2 years ago
Question Number 12 You are a landscaper working on the design of a parking lot in a new shopping center. You are measuring the l
vovikov84 [41]

Answer:

Length\: of\: D=37\frac{3}{16}  \:feet

Step-by-step explanation:

The following are the given information:

  • The handicapped spot, which is 10\frac{1}{16} feet wide and next to the curb.
  • The other three spots are 8\frac{3}{8} feet wide.
  • There are 4 dividing lines between the spots, and each measures \frac{1}{2} foot.

The Median D therefore will be a sum of the following:

  • The width of the Handicapped Spot
  • 3 X The width of the other spots
  • 4 X The width of the dividing line

= 10\frac{1}{16} + (3 X 8\frac{3}{8})+(4 X\frac{1}{2})\\=\frac{161}{16} +  \frac{3 X 67}{8}+\frac{4}{2}\\=\frac{161}{16} +  \frac{201}{8}+\frac{4}{2}\\=\frac{161+402+32}{16}\\=\frac{595}{16}\\Length\: of\: D=37\frac{3}{16}  \:feet

7 0
2 years ago
The length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58° to 3
viva [34]

Answer:

119.45 m

Step-by-step explanation:

Given:

When angle of elevation of the sun changes from 58° to 36° the length of shadow of a pole increases by 90 m.

To find:

Length of pole = ?

Solution:

Kindly refer to the attached image.

\triangle ABC represents the 1st angle of elevation of sun i.e.  58°

\triangle ABD represents the 2nd angle of elevation of sun i.e.  36°

Change in shadow is represented by CD = 90 m

Let height of pole, AB = h m

Let side BC = x m

Now, let us apply tangent rules in \triangle ABC, \triangle ABD one by one:

tan\theta = \dfrac{Perpendicular}{Base}\\\Rightarrow tan58^\circ=\dfrac{AB}{BC}\\\Rightarrow tan58^\circ=\dfrac{h}{x}\\\Rightarrow x = 0.624h ..... (1)

tan36^\circ = \dfrac{h}{x+90}

Putting value of x using equation (1):

tan36^\circ = \dfrac{h}{0.624h+90}\\\Rightarrow 0.726\times 0.624h+0.726\times 90 = h\\\Rightarrow h-0.453h =65.34\\\Rightarrow \bold{h = 119.45\ m}

119.45 m is the height of pole.

7 0
2 years ago
Factor the expression 28r+42s-35
SIZIF [17.4K]

Answer:7(4r+6s-5)

Step-by-step explanation:

The GCF is 7

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Each garden will have 12 sections of flowers
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