Answer:
Well, I don't think I can remember EVERY skill I was taught through the years but in Kindergarten we used Number Sense so we could accurately... also there's estimation and of course PEMDAS. I've also learned how to round up so that the solution is at least around those numbers if the skill is to be applied.
Step-by-step explanation:
I'm not sure if this'll help but go ahead and have it... just try and change it a bit so they don't get ya for plagirism
the number of cards in my friends stack is 20 total cards
Solve for n the first can be like:-NP<40+70. -NP<110 the second one can be like : 4w-7k =28. solve for k and then, -7k=28-4w divide both sides by -7 that equal to k =-4-4w
A) Diagram
Below is a sketch of the recctangular lawn (the inside rectangle) and the gravel border.
6 ft + 150 yards + 6 ft
-------------------------------
| |
| --------------------- |
| | | |
| | | | 6 ft + 80 yard + 6 ft
| | | |
| --------------------- |
| |
|------------------------------|
B) How many square feet of the gravel will surround the lawn?
Conversion: 1 yard = 3 feet
=> 80 yard = 80*3 feet = 240 feet
=> 150 yard = 150 * 3 feet = 450 feet
Area of the external rectangle = (6 ft + 240 ft + 6 ft) (6 ft + 450 ft + 6 ft) = 252 ft * 462 ft = 116,424 ft^2
Area of the internal rectangle = 240 ft * 450 ft = 108,000 ft^2
Area of the gravel border = 116,424 ft^2 - 108,000 ft^2 = 8424 ft^2
answer: 8424 ft^2
C) volume
volume = area of the base * depth
2 inches = 2/12 ft = 1/6 ft
=> volume = 8424 ft^2 * 1/6 ft = 1404 ft^3
answer: 1404 ft^3
C) cost
1 yard^3 = $ 30
1yard ^3 = (3 feet)^3 = 27 ft^3
=> cost = $ 30 / 27 ft^3
=> 1404 ft^3 * $30 / 27 ft^3 = $ 1560
answer: $ 1560
