Answer:
a) This is an Observational Study because in this kind of study investigators observe subjects and measure variables of interest without assigning treatments to the subjects. Here, the Gilham et al. (2005) studied two different groups where no treatment or intervention was done. These groups were independent of each other.
b) proportions of children with significant social activity in children with acute lymphoblastic leukemia = 1020/1272 = 0.80
proportions of children with significant social activity in children without acute lymphoblastic leukemia = 5343/6238 = 0.86
c) Odds ratio can be calculated using the following formula:
OR= \frac{a/b}{c/d}
where: a - Number in exposed group with positive outcome(here this means number of children with significant social activity associated with acute lymphoblastic leukemia)
b- Number of children without social activity having with acute lymphoblastic leukemia
c- Number of children with social activity having without acute lymphoblastic leukemia
d- Number of children without social activity having without acute lymphoblastic leukemia
OR= \frac{1020/252}{5343/895}
OR= 0.6780
d) The 95% confidence interval of this Odds Ratio is 0.5807 to 0.7917.
e) Since the odds ratio lies in this confidence interval indicate that the amount of social activity is associated with acute lymphoblastic leukemia. The children with more social activity have a higher occurrence of acute lymphoblastic leukemia.
Answer:
Cooper needs 39.8 mL milk for his recipe
Step-by-step explanation:
Let B be the quantity of butter
and
m be the quantity of milk
<u>So according to given statement the whole mixture measures 70.4 mL while butter measures 30.6mL</u>
so,
B+m = 70.4
30.6 + m = 70.4
m = 70.4 - 30.6
m = 39.8 mL
Cooper needs 39.8 mL milk for his recipe ..
No, this rel. is not proportional because of the addition involved ("plus 1 lb for each guest").
A proportional rel. features mult. only.