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Rom4ik [11]
2 years ago
12

Suzanne owns a small business that employs 555 other people. Suzanne makes \$100{,}000$100,000dollar sign, 100, comma, 000 per y

ear, and the other 555 employees make between \$40{,}000$40,000dollar sign, 40, comma, 000 and \$50{,}000$50,000dollar sign, 50, comma, 000 per year.
A dot plot has a horizontal axis labeled, Salary, in thousands of dollars, marked from 40 to 100, in increments of 2. 1 dot is plotted above each of the following values: 40, 42, 44, 46, 48, 100. The dot above 100 is shaded purple.
Suzanne decides to leave the company and keep the other 555 salaries the same.
A dot plot has a horizontal axis labeled, Salary, in thousands of dollars, marked from 40 to 100, in increments of 2. 1 dot is plotted above each of the following values: 40, 42, 44, 46, 48.
How will removing Suzanne's salary from the data set affect the mean and median?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
The mean will decrease and the median will increase.

(Choice B)
B
The median will decrease and the mean will increase.

(Choice C)
C
Both the mean and median will decrease, but the median will decrease more than the mean.

(Choice D)
D
Both the mean and median will decrease, but the mean will decrease more than the median.
Mathematics
1 answer:
storchak [24]2 years ago
8 0
D mean will decrease
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Decrease £19064.67 by 9.5%<br> Give your answer rounded to 2 DP.
alina1380 [7]

Answer:

New amount (decrease) = £17253.53

Step-by-step explanation:

<u>Given the following data;</u>

Amount = £19064.67

Percentage = 9.5%

To find the percentage decrease;

Percentage \; cost = \frac {9.5}{100} * 19064.67

Percentage \; cost = 0.095 * 19064.67

Percentage cost = £1811.14

New amount (decrease) = Original amount - percentage cost

Substituting into the equation, we have;

New amount (decrease) = £19064.67 - £1811.14

<em>New amount (decrease) = £17253.53</em>

6 0
2 years ago
Mrs. Kato has 6 bags of dried beans and a 2-pound bag of rice in one shopping bag. In another shopping bag she has a 5-pound bag
Salsk061 [2.6K]

Answer: 3 pounds

Step-by-step explanation:

8 0
2 years ago
The cafeteria staff made sandwiches. Each sandwich had either rye or white bread, either ham or turkey, and either cheese or no
Anit [1.1K]

Answer:

1/2 (1 half)

Step-by-step explanation:

The number of different sandwiches is calculated multiplying all of the possibilities for each material used:

rye or white bread: 2 options

ham or turkey: 2 options

cheese or no cheese: 2 options

So the number of different sandwiches that can be made is 2*2*2 = 8.

From these 8 different sandwiches, 4 have cheese and 4 have no cheese, as the staff made a equal number of each type of sandwich.

So, if from 8 different type of sandwiches, 4 have cheese, the chances of Mary getting a sandwich with cheese is 4/8 = 1/2 (1 half).

8 0
2 years ago
In a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979,
Fed [463]

Answer:

we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years

Step-by-step explanation:

Given that in a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979, two groups of childless wives aged 25 to 29 were selected at random, and each was asked if she eventually planned to have a child. One group was selected from among wives married less than two years and the other from among wives married five years.

Let X be the group married less than 2 years and Y less than 5 years

                         X        Y     Total

Sample size   300   300    600

Favouring       240   288    528

p                      0.8     0.96  0.88

H_0: p_x=p_y\\H_a: p_x>p_y

p difference = -0.16

Std error for difference = \sqrt{0.88*0.12/600} =0.01327

Test statistic = p difference/std error=-6.03

p value <0.000001

Since p is less than alpha 0.05 we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years

4 0
2 years ago
According to a human modeling​ project, the distribution of foot lengths of women is approximately Normal with a mean of 23.3 ce
Yakvenalex [24]

Answer:

26.11% of women in the United States will wear a size 6 or​ smaller

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 23.3, \sigma = 1.4

In the United​ States, a​ woman's shoe size of 6 fits feet that are 22.4 centimeters long. What percentage of women in the United States will wear a size 6 or​ smaller?

This is the pvalue of Z when X = 22.4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{22.4 - 23.3}{1.4}

Z = -0.64

Z = -0.64 has a pvalue of 0.2611

26.11% of women in the United States will wear a size 6 or​ smaller

8 0
2 years ago
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