The answer to the problem is y^12
Answer:
x = 10
Step-by-step explanation:
l n 20 + l n 5 = 2 l n x
ln (20×5) = ln x²
ln(100) = lnx²
100 = x²
x = +/- 10
Since logs of negative numebrs don't exist, we reject -10
Answer:
Step-by-step explanation:
Consider the given matrix
![A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D)
Let matrix B is
![B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
It is given that
![\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
On comparing corresponding elements of both matrices, we get
Therefore, the required values are .
Answer:
9 p 4 s
Step-by-step explanation:
That's the answer.
3,000 yd3 = 200 dtl
Chapter 1: Problem Solving 17 / 21
Rates Question
12 A highway had a landslide, where 3,000 cubic yards of material fell on the road, requiring 200 dump truck loads to clear. On another highway, a slide left 40,000 cubic yards on the road. How many dump truck loads would be needed to clear this slide?
3,000 yd3 = 200 dtl
40,000 yd3 × 200 dtl = 2,667 dtl
3, 000 yd3
