Here are your measures of variability. The range is found by subtracting the highest and the lowest (29-5=24). To find the interquartile range, you will find the median of the lower half of the data and the median of the higher half of sta and subtract these 2 numbers. Here is your list. I have PUT PARENTHESES around the upper and lower quartiles: 5, 17, (18), 20, 20, 21, 23, (26), 28, 29. It is like finding the middle of the entire set of data and then finding the middle of each half. Subtract 26 and 18 to find the interquartile range of 8 touchdowns.
Answer:
50.24 yards
Step-by-step explanation:
We will use the pythagorean theorem to find hypotenuse of each of the 4 triangles.
Pythagorean Theorem is 
For Spinach area, two of the legs are 8 and 6. Solving for hypotenuse:
For watermelon area, two of the legs are 12 and 8. Solving for hypotenuse:
in red peppers area, the hypotenuse is already given as 15. But we need to find one leg since that will be the leg of the triangle in tomatoes area. Hypotenuse is 15 and one leg is 12, so the other leg is:
So, in tomatoes area, we have one leg 9 and another leg 6. Solving for hypotenuse:
Adding all the four hypotenuses, we get the length of the walkway:
Length of Walkway = 
yards
Answer:
(3)(5) + (1/3)(5) + (3)(1/4) + (1/3)(1/4)
Step-by-step explanation:
(3 1/3)(5 1/4) =
= (3 1/3)(5 + 1/4)
= (3 1/3)(5) + (3 1/3)(1/4)
= (3 + 1/3)(5) + (3 + 1/3)(1/4)
= (3)(5) + (1/3)(5) + (3)(1/4) + (1/3)(1/4)
(a) When the sequence is arithmetic, sequential terms have a common difference.
... x - 3 = (4x/3) - x . . . . differences of sequential terms are equal
... (2/3)x = 3 . . . . . . . add 3-(1/3)x
... x = 9/2 . . . . . . . . . multiply by 3/2
(The arithmetic sequence is 3, 4.5, 6. The common difference is 3/2.)
(b) When the sequence is geometric, sequential terms have a common ratio.
... x/3 = (4x/3)/x . . . . . ratios of sequential terms are equal
... x^2 = 4x . . . . . multiply by 3x
... x = 4 . . . . . . . . divide by x. (the "solution" x=0 is extraneous)
(The geometric sequence is 3, 4, 16/3. The common ratio is 4/3.)
We have the given in the problem as mentioned:
A total of 130 students and only 7 had been placed in the wrong math class.
With this given, we can easily draw the proportion of all students who have been placed in the wrong math class by estimation method and the solution is shown below:
Proportion = 7/130
