1 year ago

Translate to an inequality. Use the variable x for next year's salary.

Mathematics

1 answer:

enot [183]1 year ago

7 0

x has to be greater or equal to 16,000

x ≥ 16,000

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On a coordinate plane, 2 triangles are shown. Triangle A B C has points (negative 1, 1), (negative 4, 1) and (negative 1, 5). Tr

Reptile [31]

Answer:

The figures are congruent because a 270° rotation about the origin and then a reflection over the x-axis will map ΔABC onto ΔLMN.

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1 year ago

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Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how

Igoryamba

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune from the sun

= 4.503 × 10 ⁹ k m .

and Mercury = 5.791 × 10 ⁷ k m .

Hence neptune is ( 4.503 × 10 ⁹) ÷ (5.791 × 10 ⁷ ) times farther from the sun than mercury

i.e.( $\frac{4.503}{5.791}$ ) × 10⁹⁻⁷ times

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1 year ago

Please solve (-3×+15)+(-3×+2)

koban [17]

(-3x + 15) + (-3x + 2)
Simplify by combining like terms.
-6x + 17

-6x + 17

3 0

1 year ago

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A mill processes 27 tons of flour in 3 hours. How many tons of flour can the mill process in 8 hours if the rate of production s

Delvig [45]

There are a few ways you can go about solving this question. One way is to use the given information to find how many tons of flour can be processed in one hour. If 27 tons can be processed in 3 hours, we can do 27 divided by 3 to find that 9 tons of flour can be processed per hour. Then, if we want to see how many tons of flour can be processed in 8 hours, we can multiply 9 tons by 8 hours to get a total of 72 tons of flour.

I hope this helps.

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1 year ago

The volume inside of a sphere is V=4πr33 where r is the radius of the sphere. Your group has been asked to rearrange the formula

Semmy [17]

Answer:

Therefore,

$r=\sqrt[3]{\frac{3V}{4\pi }}$

is the required r

Step-by-step explanation:

Given:

Volume of inside of the sphere is given as

$V=\frac{4}{3} \pi r^{3}$

where r is the radius of the sphere

To Find:

r =?

Solution:

We have

$V=\frac{4}{3} \pi r^{3}$ ......Given

$3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}$

Therefore,

$r=\sqrt[3]{\frac{3V}{4\pi }}$

is the required r

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2 years ago