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Vilka [71]
2 years ago
13

Please help! You need to create a fenced off region of land for cattle to graze. The grazing area must be a total of 500 square

feet, surrounded by a fence, and in the shape of a regular polygon. Within this grazing area, the length of the apothem must be 10 feet long. Part I. Find the total perimeter of the grazing area. Part II. If the cost of the fence is $7.95 per linear foot, how much will it cost to place a fence around the entire grazing area? Part III. Suppose this grazing area is of an industrial grazing area for a major industry farm. What is the total cost to build a fence around the entire land of the large scaled farm? Include all of the necessary calculations in your final answers for Parts I, II, and III.
Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
5 0

Answer:

multiply the price and max then divide it to get the total cost

Step-by-step explanation:

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On a coordinate plane, solid circles appear at the following points: (negative 4, 2), (negative 2, 2), (negative 1, 4), (1, 1),
Elenna [48]

Answer:

(1, 3)

Step-by-step explanation:

Given:

A circle with the following points on it-

(4, 2), (-2, 2), (-1, 4), (1, 1), (1, 3), (2, -3).

A function is just like a machine that gives an output for a given unique input.  No two outputs can have the same input.

The input to a function is called the domain of a given function. The output of a function is called its range.

The domain is represented by the 'x' coordinate and the range is represented by the 'y' coordinate.

So, the domain is the independent variable and range depends on the values of the domain.

Now, a relation of set of points represents a function only if all the 'x' coordinates of the set of ordered pairs are different.

Now, in the relation above, the ordered pairs (1, 1) and (1, 3) have the same input. So removing either of the two will make the relation a function.

So, the correct option is (1, 3).

5 0
2 years ago
Read 2 more answers
Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) + 24 = 0? u2 – 11u + 24 = 0 where u = (x2 – 1) (u2)2 – 11(u2) +
Vinvika [58]
<span><span>u2</span> – 11u + 24 = 0 where u = (x2 – 1) the first awnser, a.</span>
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7. John, Paul, and George are having a disagreement over interest rates. John
gayaneshka [121]
John Paul is correct
7 0
1 year ago
Juana tiene en su tienda un costal con 28 libras de azucar.Hizo seis paquetes de 2,5 kg cada uno,de los cuales vendio cinco.¿Cua
Likurg_2 [28]

Answer:

Al comienzo Juana tiene 28 libras de azúcar.

Ella hace 6 paquetes de 2.5kg cada paquete.

Entonces, entre los 6 paquetes, hay:

6*2.5kg = 15kg de azúcar.

Ahora el problema es que tenemos dos unidades distintas, kilogramos y libras.

Aca podemos usar la relación:

1k = 2.2lb.

Entonces 15kg de azúcar son 15 veces 2.2 libras:

15kg = 15*2.2lb = 33lb.

Esto nos da mas de lo que hay originalmente en el costal.

Ahora si lo pensamos como:

Solo vendió 5 paquetes de 2.5kg, entonces el sobrante queda en el costal inicial:

5*2.5kg = 12.5kg

De vuelta, 1kg = 2.2lb

12.5kg = 12.5*2.2lb = 27.5lb

En este caso hay un sobrante de:

28lb - 27.5lb = 0.5lb

6 0
2 years ago
4) An arithmetic sequence has a 7th term of 54 and a 13th term of 94. Find the common difference
san4es73 [151]

Answer:

20/3

Step-by-step explanation:

Every nth term takes the form of  a + n*d, where a is the first  term.

So 7th term = (54 = a + 7d), 13th term = (94 = a + 13d).

equate them both:

94 - 13d = 54 - 7d

40 = 6d

d = 40/6

6 0
1 year ago
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