For this case, the first thing we must do is define variables.
We have then:
t: the time in minutes
k: the number of kilometers
The relationship between both variables is direct.
Therefore, the function is:
Where, "c" is a constant of proportionality.
To determine "c" we use the following data:
After running for 18 minutes, she completes 2 kilometers.
Substituting values:
Clearing c we have:
Then, the equation is given by:
Answer:
An equation that can be used to represent k, the number of kilometers Julissa runs in t minutes is:
Answer:
17.78 meters
Step-by-step explanation:
Let
x ----> the horizontal distance, in meters, to home plate
----> the angle of vision
we know that
----> by TOA (opposite side divided by the adjacent side)
we have
substitute
solve for x
Answer: There are 3 quarts of concentrate and 9 quarts of water.
Step-by-step explanation:
Since we have given that
Ratio of number of quarts of water to number of quarts of concentrate is
3:1
Number of quarts of orange juice from concentrate and water = 12 quarts
So, the number of quarts of concentrate would be
the number of quarts of water would be
Hence, there are 3 quarts of concentrate and 9 quarts of water.
Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².
It is given here that there is 1/3 probability of professional baseball player will get a hit. Hence if at least three hits are gained out of 5 attempts, the calculation goes: 5C3* (1/3)^3*(2/3)^2 + 5C4* (1/3)^4*(2/3)^1 +5C5 *<span>(1/3)^5*(2/3)^0 equal to 0.21. </span>
