At the time the rocket hits the ground h=0, given that h=-16t²+320t+32
when h=0, our equation will be:
-16t²+320t+32=0
solving the above by completing square method we proceed as follows;
-16t²+320t+32=0
divide though by -16 we get
t²-20t-2=0
t²-20t=2
but
c=(-b/2a)^2
c=(20/2)^2
c=100
hence:
t²-20t+100=100+2
(t-10)(t-10)=102
√(t-10)²=√102
t-10=√102
hence
t=10+/-√102
t~20.1 or -0.1
since it must have taken long, then the answer is 20.1 sec
<u>Answer:</u>
The maximum number of turkey sandwiches Ben could have sold is 6.
<u>Step-by-step explanation:</u>
We are given that turkey sandwiches cost $2.50 and veggie wraps cost $3.50 at a snack stand.
Given the information, we are to find the maximum value of turkey sandwiches Ben could have sold.

Number of veggie wraps sold (y) = 4
2.50x + 3.50(4) < 30
2.50x + 14 < 30
<u> - 14 -14
</u>
2.50x < 16


The maximum number of turkey sandwiches Ben could have sold is 6.
Answer:
Step-by-step explanation:
We would apply the formula for exponential decay which is expressed as
A = P(1 - r)^t
Where
A represents the value of the car after t years.
t represents the number of years.
P represents the initial value of the car.
r represents rate of decay.
From the information given,
A = $2700
P = $20300
n = 2004 - 1997 = 7 years
Therefore,
20300 = 2700(1 - r)^7
20300/2700 = (1 - r)^7
7.519 = (1 - r)^7
Taking log of both sides, it becomes
Log 7.519 = 7 log(1 - r)
0.876 = 7 log(1 - r)
Log (1 - r) = 0.876/7 = 0.125
Taking inverse log of both sides, it becomes
10^log1 - r = 10^0.125
1 - r = 1.33
r = 1.33 - 1 = 0.33
The expression would be
A = 20300(1 - 0.33)^t
A = 20300(0.67)^t
Therefore, in 2007,
t = 2007 - 1997 = 10 years
The value would be
A = 20300(0.67)^10
A = $370
Answer:
y= - 1/2 (negative half) = -0.5
Step-by-step explanation:
−6y+3(12y)=20(y−1)+15
Multiply 3 and 12 to get 36.
−6y+36y=20(y−1)+15
Combine −6y and 36y to get 30y.
30y=20(y−1)+15
Use the distributive property to multiply 20 by y−1.
30y=20y−20+15
Add −20 and 15 to get −5.
30y=20y−5
Subtract 20y from both sides.
30y−20y=−5
Combine 30y and −20y to get 10y.
10y=−5
Divide both sides by 10
y= -5/10
Reduce the fraction -5/10 = -0.5 to lowest terms by extracting and cancelling out 5 .