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OLEGan [10]
2 years ago
6

Write the multiple regression equation for miles per gallon as the response variable. Use weight and horsepower as predictor var

iables. See Step 5 in the Python script. How might the car rental company use this model
Mathematics
1 answer:
Naily [24]2 years ago
8 0

Answer:

Step-by-step explanation:

Response Variable: Miles per gallon

Predictor Variables: Weight, Horsepower

The multiple regression equation would be: M = aW + bH + c

where M = miles per gallon

a = slope of the graph of W on M OR rate of change in M due to change in W

W = weight

b = slope of the graph of H on M OR rate of change in M due to change in H

H = horsepower

c = intercept of M on the y-axis OR constant variable

How might the car rental company use this model?

The car rental company might use the regression model to determine the following:

- Effect of weight (of car) on miles run per gallon (of premium motor spirit)

- Effect of horsepower on miles per gallon; etc.

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2 years ago
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gayaneshka [121]
Number of students that chose art = 100-(22+26) = 100- 48 = 52

so percentage of students who chose art = 52%
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Which of the following is the expansion of (3c + d2)6?
vovangra [49]

Answer: Option A) 729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12} is the correct expansion.

Explanation:

on applying binomial theorem,  (a+b)^n=\sum_{r=0}^{n} \frac{n!}{r!(n-r)!} a^{n-r} b^r

Here a=3c, b=d^2 and n=6,

Thus, (3c+d^2)^6=\sum_{r=0}^{6} \frac{6!}{r!(6-r)!} (3c)^{n-r} (d^2)^r

⇒ (3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6

⇒(3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}

⇒(3c+d^2)^6=(3c)^6.d^0+\frac{720}{120} (3c)^5.d^2+\frac{720}{48} (3c)^4.d^4+\frac{720}{36} (3c)^3.d^6+\frac{720}{48} (3c)^2.d^8+\frac{720}{120} (3c).d^{10}+.d^{12}

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