Brenda has a square-shaped photo frame. If the area of the square frame is 123 square inches, which statement is true?

Pecans that cost $28.50 per kilogram were mixed with almonds that cost $22.25 per kilogram. How many kilograms of each were used

atroni [7]

Answer:

The pecans used in the mixture = 8 kg

The almonds used in the mixture = 17 kg

Step-by-step explanation:

The cost of per kg of pecans = $28.50

The cost of per kg of almonds = $22.25

Now, total weight of mixture = 25 kg

Let us assume the weight of pecans in the mixture = m kg

So, the amount of almonds in the mixture = Total weight - Weight of Pecans

= (25 - m) kg

Now, cost of m kg pecans = m x ( cost of 1 kg pecans) = m x ( $ 28.50)

= 28.50 m

cost of (25- m) kg almonds = (25 -m) x ( cost of 1 kg almonds)

= (25 - m) x ( $ 22.25)

= 556.25 - 22.25 m

Total cost of 25 kg of mixture = 25 x ( $24.25) = $606.25

Now, Total Cost of (almonds + Pecans) = Total cost of mixture

⇒28.50 m + 556.25 - 22.25 m = $606.25

or,6.25 m = 50

or, m = 50/6.25 = 8

Hence, the pecans used in the mixture = m = 8 kg

And the almonds used in the mixture = (25 - m) = 25 - 8 = 17 kg

5 0

1 year ago

From generation to generation, the mean age when smokers first start to smoke varies. However, the standard deviation of that ag

Jlenok [28]

Answer:

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the the actual mean starting age of smokers is significantly lower than 19.

Step-by-step explanation:

1) Data given and notation

$\bar X=18.1$ represent the mean age when smokers first start to smoke varies

$s=1.3$ represent the standard deviation for the sample

$\sigma=2.1$ represent the population standard deviation

$n=37$ sample size

$\mu_o =5.7$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean starting age is at least 19, the system of hypothesis would be:

Null hypothesis: $\mu\geq 19$

Alternative hypothesis: $\mu < 19$

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{18.1-19}{\frac{2.1}{\sqrt{37}}}=-2.607$

Calculate the P-value

Since is a one-side lower test the p value would be:

$p_v =P(z$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the the actual mean starting age of smokers is significantly lower than 19.

4 0

2 years ago

To make one ham sandwich, tina uses one bread roll and two ham slices

igor_vitrenko [27]

Answer:

£67.78

Step-by-step explanation:

Bread - 6 x £2.87 = £17.22

Ham - 8 x £6.32 = £50.56

£17.22

+ <u>£50.56</u>

£67.78