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marshall27 [118]
2 years ago
8

The table shows the estimated number of lines of code written by computer programmers per hour when x people are working.

Mathematics
2 answers:
PilotLPTM [1.2K]2 years ago
6 0

Answer:

Hence, the model that best represents the data is:

y=26.9x-1.3

Step-by-step explanation:

We are given a table that  shows the estimated number of lines of code written by computer programmers per hour when x people are working.

We are asked to find which model best represents the data?

So for finding this we will put the value of x in each of the functions and check which hold true that which gives the value of y i.e. f(x) as is given in the table:

We are given 4 functions as:

A)

y = 47(1.191)^x

B)

y=34\times (1.204)^x

C)

y=26.9x-1.3

D)

y=27x-4

We make the table of these values at different values of x.

x                  A                 B                C               D

2              66.66          49.3            52.5           50

4             94.57            71.44           106.3         104  

6             134.14           103.57         160.1          158

8             190.27          150.14          213.9         212

10           269.91           217.64         267.7         266

12           382.85          315.5           321.5          320.

Hence, the function that best represents the data is:

Option C.

y=26.9x-1.3

Alexxandr [17]2 years ago
4 0

y = 26.9x – 1.3 is the answer i took the test


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Answer:

NOT VERY LIKELY

Step-by-step explanation:

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A supermarket has two customers waiting to pay for their purchases at counter I and one customer waiting to pay at counter II. L
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Answer:

b. 0.864

Step-by-step explanation:

Let's start defining the random variables.

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Y2 : ''Number of customers who spend more than $50 on groceries at counter 2''

If X is a binomial random variable, the probability function for X is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

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nCx is the combinatorial number define as :

nCx=\frac{n!}{x!(n-x)!}

n is the number of independent Bernoulli experiments taking place

And p is the success probability.

In counter I :

Y1 ~ Bi (n,p)

Y1 ~ Bi(2,0.2)

P(Y1=y1)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}

With y1 ∈ {0,1,2}

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In counter II :

Y2 ~ Bi (n,p)

Y2 ~ Bi (1,0.3)

P(Y2=y2)=(1Cy2)(0.3)^{y2}(0.7)^{1-y2}

With y2 ∈ {0,1}

And P( Y2 = y2 ) = 0 with y2 ∉ {0,1}

(1Cy2) with y2 = 0 and y2 = 1 is equal to 1 so the probability function for Y2 is :

P(Y2=y2)=(0.3)^{y2}(0.7)^{1-y2}

Y1 and Y2 are independent so the joint probability distribution is the product of the Y1 probability function and the Y2 probability function.

P(Y1=y1,Y2=y2)=P(Y1=y1).P(Y2=y2)

P(Y1=y1,Y2=y2)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}(0.3)^{y2}(0.7)^{1-y2}

With y1 ∈ {0,1,2} and y2 ∈ {0,1}

P( Y1 = y1 , Y2 = y2) = 0 when y1 ∉ {0,1,2} or y2 ∉ {0,1}

b. Not more than one of three customers will spend more than $50 can mathematically be expressed as :

Y1 + Y2 \leq 1

Y1 + Y2\leq 1 when Y1 = 0 and Y2 = 0 , when Y1 = 1 and Y2 = 0 and finally when Y1 = 0 and Y2 = 1

To calculate P(Y1+Y2\leq 1) we must sume all the probabilities that satisfy the equation :

P(Y1+Y2\leq 1)=P(Y1=0,Y2=0)+P(Y1=1,Y2=0)+P(Y1=0,Y2=1)

P(Y1=0,Y2=0)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{0}(0.7)^{1-0}=(0.8)^{2}(0.7)=0.448

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P(Y1+Y2\leq 1)=0.448+0.224+0.192=0.864\\P(Y1+Y2\leq 1)=0.864

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Answer:

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Step-by-step explanation:

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