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White raven [17]
2 years ago
10

Paige works at a department store and has a commission rate of 3 percent. Her sales for the quarter were $4,596. If she earns $5

0 per day and she worked 30 days in the quarter, what is the total amount she earned?
$137.88
$1,362.12
$1,500.00
$1,637.88
Mathematics
2 answers:
Karo-lina-s [1.5K]2 years ago
7 0

Answer:

Add them together and you get her total amount earned of $1,637.88

Step-by-step explanation:

ANTONII [103]2 years ago
6 0
How you would set this up would be as follows:

(50*30)+4,596*.03

The 50*30 is her earning $50 a day for 30 days. Then to find her commission earnings you multiply her sales of 4,596 times the commission rate of 3%(when you move the decimal place you get .03)

Add them together and you get her total amount earned of $1,637.88

Hope this helped!


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Alex and Nick collect baseball cards. Alex has three more than twice as many cards as Nick. Together they have 27 cards. How man
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Answer: 21

Step-by-step explanation:

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2 years ago
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If 25% of 150 is equal to 700 percent of n, then n is equal to what number?
adelina 88 [10]
25% of 150 = 37.5
700% of x = 37.5
x = 5.35714285
5 0
2 years ago
A cube-shaped water tank having 6 ft side lengths is being filled with water. The bottom is solid metal but the sides of the tan
Mekhanik [1.2K]

Answer:

0.033 ft

Step-by-step explanation:

Let g = 32.2 ft/s2 and h be the maximum height that water can be filled before the sides shatter.

Pressure is distributed from 0 to maximum at the bottom like the following equation:

P = \rho gh

So the force generated by water pressure on the side of the tank is

F = PA = \rho ghs/2

where s = 6ft is the side length of the tank. This force cannot be larger than 200lb

\rho ghs/2 \leq 200

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4 0
2 years ago
The slope of diagonal OA is ? and its equation is ?
Nimfa-mama [501]

Answer:

Slope = \frac{4}{3}

Equation of the line → y=\frac{4}{3}x

Step-by-step explanation:

Let the equation of diagonal OA is,

y = mx + b

Here, m = Slope of the line OA

b = y-intercept

Slope of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

m = \frac{y_2-y_1}{x_2-x_1}

Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,

m = \frac{4-0}{3-0}

m = \frac{4}{3}

Since, line OA is passing through the origin, y-intercept will be 0.

Therefore, equation of OA will be,

y=\frac{4}{3}x

3 0
2 years ago
among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play
kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0
2 years ago
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