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saw5 [17]
2 years ago
9

The slope of diagonal OA is ? and its equation is ?

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
3 0

Answer:

Slope = \frac{4}{3}

Equation of the line → y=\frac{4}{3}x

Step-by-step explanation:

Let the equation of diagonal OA is,

y = mx + b

Here, m = Slope of the line OA

b = y-intercept

Slope of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

m = \frac{y_2-y_1}{x_2-x_1}

Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,

m = \frac{4-0}{3-0}

m = \frac{4}{3}

Since, line OA is passing through the origin, y-intercept will be 0.

Therefore, equation of OA will be,

y=\frac{4}{3}x

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