Ask question

Ask question

All categories

aleksandrvk [35]

2 years ago

12

A scuba diver starts at 79.5 meters below the surface and descends until he reaches 108.3 meters below sea level. How many meter

s did he descend?

2 answers:

nata0808 [166]2 years ago

8 0

Answer:

28.8

Step-by-step explanation:

You are looking for the number between 108.3 and 79.5, so you have to do this 108.3-79.5

gogolik [260]2 years ago

5 0

Answer: 28.8

Brainliest pls

You might be interested in

As an example, 15,000 Men 18-34 watched program X at 7-8 pm on Monday night. 32,000 Men 18-34 had their TV on during the same ti

miv72 [106K]

Answer:

7.5 rating points

Step-by-step explanation:

The computation of the rating for Men 18-34 for program X is shown below:

Given that

Number of men 18 -34 watched a program X = 15,000 = X

Number of men 18 - 34 watched in a same time = 32,000

And, the total households in the market = 200,000 = Y

So, the rating for men 18-34 for program x is

$= \frac{X}{Y}$

$= \frac{15,000}{200,000}$

= 7.5 rating points

We simply applied the above formula

3 0

2 years ago

What is the multiplicative rate of change of the function described in the table ?

Vadim26 [7]

The answer to the question is B.

6 0

2 years ago

Read 2 more answers

A clothing store offers a free T-shirt when a customer spends $75 or more. Lyndon has already spent $36.95. Which statement best

Jet001 [13]

It would most possibly be 38.05 or less

3 0

2 years ago

Read 2 more answers

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

7nadin3 [17]

The equation of the cone should be $z=\sqrt{x^2+y^2}$ . Parameterize $S$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u\,\vec k$

with $1\le u\le2$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=u\cos v\,\vec\imath+u\sin v\,\vec\jmath-u\,\vec k$

Then the integral of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_1^2(-u\cos v\,\vec\imath-u\sin v\,\vec\jmath+u^3\,\vec k)\cdot(u\cos v\,\vec\imath+u\sin v\,\vec\jmath-u\,\vec k)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_1^2(-u^2-u^4)\,\mathrm du\,\mathrm dv$

$=\displaystyle-2\pi\int_1^2(u^2+u^4)\,\mathrm du\,\mathrm dv=\boxed{-\frac{256\pi}{15}}$

3 0

2 years ago

Read 2 more answers

What is the solution to the inequality 2 + 4/9x _> 4 + x

Vsevolod [243]

Multiply each side by 9:
18 + 4x > 36 + 9x
Subtract 18 from each side:
4x > 18 + 9x
Subtract 9x from each side:
-5x > 18
Divide each side by -5:
x < -3.6

Hope this helps!

8 0

2 years ago