Given: Circle M with inscribed Angle K J L and congruent radii JM and ML Prove: mAngle M J L = One-half (measure of arc K L) Cir
cle M is shown. Line segment J K is a diameter. Line segment J L is a secant. A line is drawn from point L to point M. What is the missing reason in step 8?
2 answers:
Answer:
We need to demontrate
As you can see in the figure below, angle MJL is an inscribed angle for Circle M, that means we can use the inscribed angle theorem to demonstrate the proposition above.
<h3>Therorem.</h3><em>The angle formed by two intersecting chords with vertex on the circumference is equal to one-half of the intercepted arc.</em>
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Notice that the theorem says a chord. However, a diameter is a chord by definition, because a chord is a segment that unites to points of the circumference, and a diameter does that too.
Therefore, based on the inscribed angle arc theorem, we have
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Answer:
1) 15cm
2) left projection/h = h/right projection
Step-by-step explanation:
Question:
1) The projections of the legs of a right triangle on the hypotenuse have lengths of 9 cm and 25 cm. Find the length of the height at the top of the right angle.
2) In a right triangle the length of the hypotenuse is 34 cm, and the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75. Calculate the length of the height corresponding to the hypotenuse.
Solution
1) The length of the height of a right angle triangle is also called the altitude.
Since there are no diagrams in the question, I sent a diagram of the right angle as an attachment to the solution.
The projections of the legs are 25cm and 9cm.
Hence, the longer projection length AD = 25cm and the shorter projection length DB = 9cm
In a right triangle, the altitude (height) drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of the altitude is the
geometric mean of these two segments (the two projections) and it's given by:
left projection/h = h/right projection
AD/h = h/DB
25/h = h/9
Cross multiply
h^2 = 25×9
h =√225 = 15cm
The length of the height at the top of the triangle = 15cm
2) Length of hypotenuse = 34
From the question, the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75.
There is an error with the figures because the sum of the length of the projection of the legs should be equal to the hypotenuse but it isn't in this case.
To calculate the length of the height corresponding to the hypotenuse, we would use the same formula above.
left projection/h = h/right projection
To find each leg using question 1 above, each leg of the triangle is the mean proportional between the hypotenuse and the part of the hypotenuse directly below the leg.
Hypotenuse =34cm
Hyp/leg = leg/part
To find leg y, part for leg y = 25cm
34/y = y/25
y^2 = 34×25 = 850
y = √850 = 29.2cm
To find leg x, part for leg x = 9cm
34/y = y/9
y^2 = 34×9 = 306
y = √306 = 17.5cm
