gg easy
the legs of a triangle are related as
wehre a, b, and c are the legs and the hypotonuse of a triangle respectively
let's find some stuff
one easy way is to find a rational value for c find values of a and b
lets pick c=5


now split up 25 into 2 things that don't have rational square roots
if we say
and
then we get
and
(which are both irrational)
Answer:
150 oz.
Step-by-step explanation:
There are already 150 ounces of alloy of nickel.
Of this 150 oz, 70% is pure i.e. nickel content = 150(0.7) = 105 oz
Now available is
Nickel Other metals
105 45
Let x oz of pure nickel is added.
Then new alloy will have 105+x oz nickel in total of 150+x oz.
Percentage pure = 
Simplify to get

Hence answer is 150 oz should be added.
Answer:
Step-by-step explanation:
n + q = 20
.05n + .25q = 3.00
5n + 25q = 300
n + q = 20
5n + 25q = 300
-5n - 5q = -100
20q = 200
q = 10 quarters
n + 10 = 20
n = 10 nickels
(10 nickels, 10 quarters)
<span>Let L be the number of yards on a roll of lace ribbon.
Let S be the number of yards on a roll of satin ribbon.
We can set up two equations.
equation 1: 3L + 2S = 120 yards
equation 2: 2L + 4S = 160 yards
We can multiply (equation 1) by 2 and subtract (equation 2).
equation 1: 6L + 4S = 240 yards
equation 2: 2L + 4S = 160 yards
4L = 80 yards
L = 20 yards
equation 1: 3L + 2S = 120 yards
3(20 yards) + 2S = 120 yards
2S = 60 yards
S = 30 yards
There are 20 yards on a roll of lace ribbon.
There are 30 yards on a roll of satin ribbon.</span>
Using a graphing tool
Let's graph each of the cases to determine the solution of the problem
<u>case A)</u>
see the attached figure N 
The range is the interval--------> (0,∞)

therefore
the function
is not the solution
<u>case B)</u> 
see the attached figure N
The range is the interval--------> (0,∞)

therefore
the function
is not the solution
<u>case C)</u>
see the attached figure N
The range is the interval--------> (-∞,3)

therefore
the function
is the solution
<u>case D)</u>
see the attached figure N
The range is the interval--------> (-3,∞)

therefore
the function
is not the solution
<u>the answer is</u>