Answer: Expected value of the daily cost of operating the machine is 235.264.
Step-by-step explanation:
Since we have given that
E[x]= 0.96 repairs per day
And Var[x] = 0.96 repairs per day.

![E[c]=160+40E[x^2]\\\\E[c]=160+40(Var[x]+(E[x])^2)\\\\E[c]=160+40(0.96+0.96^2)\\\\E[c]=235.264](https://tex.z-dn.net/?f=E%5Bc%5D%3D160%2B40E%5Bx%5E2%5D%5C%5C%5C%5CE%5Bc%5D%3D160%2B40%28Var%5Bx%5D%2B%28E%5Bx%5D%29%5E2%29%5C%5C%5C%5CE%5Bc%5D%3D160%2B40%280.96%2B0.96%5E2%29%5C%5C%5C%5CE%5Bc%5D%3D235.264)
Hence, Expected value of the daily cost of operating the machine is 235.264.
Answer:
number of shells zoe gives to dev = 7
number of shells zoe is left with = 55-7= 48
number of shells dev has = 9+7=16
Step-by-step explanation:
let the initial number of shells that dev has be A, and initial number of shells that zoe has be B.
let the number of shells that zoe gives to dev be x.
after giiving x shells zoe is left with 3 times the number of shell as that of dev.
therefore number of shells with zoe = 3×number of shells with dev.
number of shells with zoe = initial shells - x = 55-x
number of shells with dev = initial shells + number of shells he gets
= 9+x
therefore (55-x)=3×(9+x)
55-x = 27+3x
55-27=3x+x
4x = 28
x= 7
therefore number of shells zoe gives to dev = 7
number of shells zoe is left with = 55-7= 48
number of shells dev has = 9+7=16
The domain of a function is the set of the possible input values of the function. For example: consider the function f(x) = cos x, the domain of the function is the set of possible values of x.
The cosine function takes x values from all real numbers.
Therefore, the domain of the cosine function is a real numbers.
answer: 6 is the greatest number of snack bags that Destiny can make. Step-by-step
Step-by-step explanation:
The first gift is a box of 18 chocolate candy bars, and the second gift is a pack of 12 cookies.
Answer:Multiply by the reciprocal, also sometimes referred to as "Keep, Change, Flip." Here is how it works. You rewrite the division question as a multiplication question by flipping the second fraction over. Next, keep the first number, change the division to multiplication and then flip the second fraction over.
Step-by-step explanation: