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12345 [234]
2 years ago
9

Which expression is equivalent to (x^6y^8)^3\x^2y^2

Mathematics
2 answers:
BARSIC [14]2 years ago
8 0

Answer: x^{16}\ y^{22}

Step-by-step explanation:

The given expression : \dfrac{(x^6y^8)^3}{x^2y^2}

Using identity , (a^m)^n=a^{mn} , we have

{(x^6y^8)^3=x^{6\times3}\ y^{8\times3}\\\\=x^{18}\ y^{24}

Now, \dfrac{(x^6y^8)^3}{x^2y^2}=\dfrac{x^{18}\ y^{24}}{x^2\ y^2}

( its also an equivalent expression to given expression.)

Using identity , \dfrac{a^n}{a^m}=a^{n-m} , we have

\dfrac{x^{18}\ y^{24}}{x^2\ y^2}=x^{18-2}\ y^{24-2}\\\\=x^{16}\ y^{22}

Hence, the expression is equivalent to given expression :

x^{16}\ y^{22}

Damm [24]2 years ago
5 0

Answer:

\large\boxed{\dfrac{(x^6y^8)^3}{x^2y^2}=x^{16}y^{22}}

Step-by-step explanation:

\dfrac{(x^6y^8)^3}{x^2y^2}\qquad\text{use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=\dfrac{(x^6)^3(y^8)^3}{x^2y^2}=\dfrac{x^{(6)(3)}y^{(8)(3)}}{x^2y^2}=\dfrac{x^{18}y^{24}}{x^2y^2}\qquad\text{use}\ \dfrac{a^m}{a^n}=a^{m-n}\\\\=x^{18-2}y^{24-2}=x^{16}y^{22}

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The manager of an industrial plant is planning to buy a new machine. For each day’s operation, the number of repairs X, that the
horsena [70]

Answer:  Expected value of the daily cost of operating the machine is 235.264.

Step-by-step explanation:

Since we have given that

E[x]= 0.96 repairs per day

And Var[x] = 0.96 repairs per day.

C=160+40x^2

E[c]=160+40E[x^2]\\\\E[c]=160+40(Var[x]+(E[x])^2)\\\\E[c]=160+40(0.96+0.96^2)\\\\E[c]=235.264

Hence, Expected value of the daily cost of operating the machine is 235.264.

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Dev has 9 shells. Zoe has 55 shells, Zoe gives some shells to Dev. Now zoe has 3 times as many shells as dev. How many shells do
Goryan [66]

Answer:

number of shells zoe gives to dev  = 7

number of shells zoe is left with  = 55-7= 48

number of shells dev has = 9+7=16

Step-by-step explanation:

let the initial number of shells that dev has be A, and initial number of shells that zoe has be B.

let the number of shells that zoe gives to dev be x.

after giiving x shells zoe is left with 3 times the number of shell as that of dev.

therefore number of shells with zoe = 3×number of shells with dev.

number of shells with zoe = initial shells - x = 55-x

number of shells with dev = initial shells + number of shells he gets

                                            = 9+x

therefore (55-x)=3×(9+x)

55-x = 27+3x

55-27=3x+x

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therefore number of shells zoe gives to dev  = 7

number of shells zoe is left with  = 55-7= 48

number of shells dev has = 9+7=16

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The domain of a function is the set of the possible input values of the function. For example: consider the function f(x) = cos x, the domain of the function is the set of possible values of x.

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