The answer is <span>$103.
To determine </span><span> how much Eileen will spend on gasoline, first we need to calculate how many gallons she needs.
If she drives 850 miles and </span><span>her car gets 23 miles per gallon, we can use the proportion:
850 miles : x gallons = 23 miles : 1 gallon
Crossing the products:
x = 850 miles </span>× 1 gallon ÷ 23 miles
x = 36.96 gallons
Thus, Eileen needs 36.96 gallons of gas. If the cost per gallon of gas is$2.79, using the proportion:
36.96 gallons : x = 1 gallon : <span>$2.79
x = 36.96 gallons </span>× $2.79 <span>÷ 1 gallon
x = </span>$103.12
x ≈ $<span>103</span>
An exterior angle of a triangle is an angle formed by one side of the triangle and the extension of an adjacent side of the triangle.
FACTS:
- Every triangle has 6 exterior angles, two at each vertex.
- Notice that the "outside" angles that are "vertical" to the angles inside the triangle are NOT called exterior angles of a triangle.
1. Angles 1, 5 and 6 are inteior angles of the given triangle.
2. Angle 3 is vertical to the interior angle 5.
3. Angles 2 and 4 are exterior angles of the triangle.
Answer: correct options are A and B.
Answer:
OC. $57.28
Step-by-step explanation:
It depends on how much she sells them for.
Let's say Anne sells them for $x.
Then her profit is:
8x-(8*7.16)
=8x-57.28
To make a minimum to at least make even is $57.28 and sell for $7.16 a piece.
From -∞ to -4 the blue line is above the X axis which means it is >0
The blue line is negative between -4 and -3
This would make the correct answer: F(x) > 0 over the interval (-∞,-4)
Answer:
Step-by-step explanation:
Given g (x) = 
and 
, we are to find 
First we need to get 
Hence 
Also given f(x) = x and g(x) = 1/x, we are to find 
For the pair of function f(x) = 2/x and g(x) = 2/x
f(g(x)) = f(2/x)
f(2/x) = 2/(2/x)
f(2/x) = 2*x/2
f(2/x) = x
Hence f(g(x)) = x
For the pair of function f(x) = x-2/3 and g(x) = 2-3x
f(g(x)) = f(2-3x)
f(2-3x) = (2-3x-2)/3
f(2-3x) = -3x/3
f(2-3x) = -x
f(g(x)) = -x for the pair of function
For the pair of function f(x) = x/2 - 2 and g(x) = x/2 + 2
f(g(x)) = f(x/2 + 2)
f(x/2 + 2) = f((x+4)/2)
f((x+4)/2) = [(x+4)/2]/2 - 2
f((x+4)/2) = (x+4)/4 - 2
find the LCM
f((x+4)/2) = [(x+4)-8]/4
f((x+4)/2) = (x-4)/4
Hence f(g(x)) for the pair of function is (x-4)/4
