Answer:
The lengths from 32.1cm to 46.5cm covers 99.7% of this distribution.
Step-by-step explanation:
The 68-95-99.7 rule states that, for normally distributed measures:
68% of the values are within 1 standard deviation of the mean.
95% of the values are within 2 standard deviations of the mean.
99.7% of the values are within 3 standard deviations of the mean.
(a) What range of lengths covers almost all, 99.7%, of this distribution?
Those are those values within 3 standard deviations of the mean. So
From A to B, in which
The lengths from 32.1cm to 46.5cm covers 99.7% of this distribution.
Answer:
7.5
Step-by-step explanation:
7.2 + 8.5 + 7.0 + 8.1 + 6.7 = 37.5
37.5÷5 = 7.5
A = 6
x^2 + 6x is equal to x(x+6)
b=2
Denominator and numerator of the first term are multiplied by x.
c=6
Second term is multiplied by (x-6)/(x-6)
d=2
Now that they have the same denominator, the two terms are combined. 2 is the coefficient of the first term
e=6
In the same way as d is carried over from b, e is carried over from c.
f = 6
2x - x + 6 = x + 6
g = 1
We factor out the (x+6) from the numerator and denominator
Answer:
Positive Linear Association
Step-by-step explanation:
It was right on Khan
Let the no. Of boys=x and that of girls=y.
The total no. Of students = x+y .
As given by statement the no. Of boys=x={(x+y)/3} + 5
This implies that
X=(x+y+15)/3
Also we know that x/y = 2/3 therefore
From this equation we get x=2y/3 and y=3x/2
By method of substitution we get
X=(x+3x/2+15)/3
•x=(15x+90)/2
•2x=15x+90
•-13x=90
X= -90/13
Now. Y= 3x/2=-270/26
Therefore total
no. Of students= -270/26+(-90/13)
•no. Of students= -450/26
According to me this is an imaginary question i mean how can their be a negative person
